lib.types.defaultTypeMerge: refactor functor.{payload,wrapped} merging (#350906)
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commit
b234fd831a
@ -516,6 +516,10 @@ checkConfigError 'The option .theOption.nested. in .other.nix. is already declar
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# Test that types.optionType leaves types untouched as long as they don't need to be merged
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checkConfigOutput 'ok' config.freeformItems.foo.bar ./adhoc-freeformType-survives-type-merge.nix
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# Test that specifying both functor.wrapped and functor.payload isn't allowed
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checkConfigError 'Type foo defines both `functor.payload` and `functor.wrapped` at the same time, which is not supported.' config.result ./default-type-merge-both.nix
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# Anonymous submodules don't get nixed by import resolution/deduplication
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# because of an `extendModules` bug, issue 168767.
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checkConfigOutput '^1$' config.sub.specialisation.value ./extendModules-168767-imports.nix
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28
lib/tests/modules/default-type-merge-both.nix
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28
lib/tests/modules/default-type-merge-both.nix
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@ -0,0 +1,28 @@
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{ lib, options, ... }:
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let
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foo = lib.mkOptionType {
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name = "foo";
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functor = lib.types.defaultFunctor "foo" // {
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wrapped = lib.types.int;
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payload = 10;
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};
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};
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in
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{
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imports = [
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{
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options.foo = lib.mkOption {
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type = foo;
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};
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}
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{
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options.foo = lib.mkOption {
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type = foo;
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};
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}
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];
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options.result = lib.mkOption {
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default = builtins.seq options.foo null;
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};
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}
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@ -83,23 +83,37 @@ rec {
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# Default type merging function
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# takes two type functors and return the merged type
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defaultTypeMerge = f: f':
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let wrapped = f.wrapped.typeMerge f'.wrapped.functor;
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payload = f.binOp f.payload f'.payload;
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let mergedWrapped = f.wrapped.typeMerge f'.wrapped.functor;
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mergedPayload = f.binOp f.payload f'.payload;
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hasPayload = assert (f'.payload != null) == (f.payload != null); f.payload != null;
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hasWrapped = assert (f'.wrapped != null) == (f.wrapped != null); f.wrapped != null;
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in
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# cannot merge different types
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# Abort early: cannot merge different types
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if f.name != f'.name
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then null
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# simple types
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else if (f.wrapped == null && f'.wrapped == null)
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&& (f.payload == null && f'.payload == null)
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then f.type
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# composed types
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else if (f.wrapped != null && f'.wrapped != null) && (wrapped != null)
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then f.type wrapped
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# value types
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else if (f.payload != null && f'.payload != null) && (payload != null)
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then f.type payload
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else null;
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else
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if hasPayload then
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if hasWrapped then
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# Has both wrapped and payload
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throw ''
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Type ${f.name} defines both `functor.payload` and `functor.wrapped` at the same time, which is not supported.
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Use either `functor.payload` or `functor.wrapped` but not both.
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If your code worked before remove `functor.payload` from the type definition.
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''
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else
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# Has payload
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if mergedPayload == null then null else f.type mergedPayload
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else
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if hasWrapped then
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# Has wrapped
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# TODO(@hsjobeki): This could also be a warning and removed in the future
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if mergedWrapped == null then null else f.type mergedWrapped
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else
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f.type;
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# Default type functor
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defaultFunctor = name: {
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