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ee46f135a9
The existing implementation outputs inline cost iff function cannot be inlined with Debug['m'] > 1, the cost info is also useful if the function is inlineable. Fixes #36780 Change-Id: Ic96f6baf96aee25fb4b33d31d4d644dc2310e536 Reviewed-on: https://go-review.googlesource.com/c/go/+/216778 Run-TryBot: Alberto Donizetti <alb.donizetti@gmail.com> TryBot-Result: Gobot Gobot <gobot@golang.org> Reviewed-by: Josh Bleecher Snyder <josharian@gmail.com>
25 lines
916 B
Go
25 lines
916 B
Go
//errorcheck -0 -m -m
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// Copyright 2018 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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package main
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//go:norace
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func Foo(x int) int { // ERROR "can inline Foo with cost .* as: func\(int\) int { return x \* \(x \+ 1\) \* \(x \+ 2\) }$"
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return x * (x + 1) * (x + 2)
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}
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func Bar(x int) int { // ERROR "can inline Bar with cost .* as: func\(int\) int { return x \* \(x \+ 1\) \* \(x \+ 2\) }$"
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return x * (x + 1) * (x + 2)
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}
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var x = 5
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//go:noinline Provide a clean, constant reason for not inlining main
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func main() { // ERROR "cannot inline main: marked go:noinline$"
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println("Foo(", x, ")=", Foo(x)) // ERROR "inlining call to Foo func\(int\) int { return x \* \(x \+ 1\) \* \(x \+ 2\) }$"
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println("Bar(", x, ")=", Bar(x)) // ERROR "inlining call to Bar func\(int\) int { return x \* \(x \+ 1\) \* \(x \+ 2\) }$"
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}
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