mirror of
https://github.com/golang/go
synced 2024-11-22 04:34:39 -07:00
1fa4173444
Shame on me: I fixed the same bug in 6l in 8691fcc6a66e (https://golang.org/cl/2609041) and neglected to look at 5l and 8l to see if they were affected. On the positive side, the check I added in that CL is the one that detected this bug. Fixes #1457. R=ken2 CC=golang-dev https://golang.org/cl/3981052
100 lines
1.7 KiB
Go
100 lines
1.7 KiB
Go
// $G $D/$F.go && $L $F.$A && ./$A.out
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// Copyright 2009 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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// Try to tickle stack splitting bugs by doing
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// go, defer, and closure calls at different stack depths.
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package main
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type T [20]int
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func g(c chan int, t T) {
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s := 0
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for i := 0; i < len(t); i++ {
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s += t[i]
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}
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c <- s
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}
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func d(t T) {
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s := 0
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for i := 0; i < len(t); i++ {
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s += t[i]
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}
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if s != len(t) {
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println("bad defer", s)
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panic("fail")
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}
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}
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func f0() {
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// likely to make a new stack for f0,
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// because the call to f1 puts 3000 bytes
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// in our frame.
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f1()
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}
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func f1() [3000]byte {
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// likely to make a new stack for f1,
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// because 3000 bytes were used by f0
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// and we need 3000 more for the call
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// to f2. if the call to morestack in f1
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// does not pass the frame size, the new
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// stack (default size 5k) will not be big
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// enough for the frame, and the morestack
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// check in f2 will die, if we get that far
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// without faulting.
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f2()
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return [3000]byte{}
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}
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func f2() [3000]byte {
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// just take up space
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return [3000]byte{}
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}
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var c = make(chan int)
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var t T
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var b = []byte{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
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func recur(n int) {
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ss := string(b)
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if len(ss) != len(b) {
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panic("bad []byte -> string")
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}
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go g(c, t)
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f0()
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s := <-c
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if s != len(t) {
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println("bad go", s)
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panic("fail")
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}
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f := func(t T) int {
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s := 0
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for i := 0; i < len(t); i++ {
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s += t[i]
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}
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s += n
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return s
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}
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s = f(t)
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if s != len(t)+n {
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println("bad func", s, "at level", n)
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panic("fail")
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}
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if n > 0 {
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recur(n - 1)
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}
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defer d(t)
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}
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func main() {
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for i := 0; i < len(t); i++ {
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t[i] = 1
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}
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recur(8000)
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}
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