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go/test/fixedbugs/issue24651b.go
TennyZhuang ee46f135a9 cmd/compile: output cost while inlining function with Debug['m'] > 1
The existing implementation outputs inline cost iff function cannot be inlined with Debug['m'] > 1, the cost info is also useful if the function is inlineable.

Fixes #36780

Change-Id: Ic96f6baf96aee25fb4b33d31d4d644dc2310e536
Reviewed-on: https://go-review.googlesource.com/c/go/+/216778
Run-TryBot: Alberto Donizetti <alb.donizetti@gmail.com>
TryBot-Result: Gobot Gobot <gobot@golang.org>
Reviewed-by: Josh Bleecher Snyder <josharian@gmail.com>
2020-02-26 14:44:24 +00:00

25 lines
916 B
Go

//errorcheck -0 -m -m
// Copyright 2018 The Go Authors. All rights reserved.
// Use of this source code is governed by a BSD-style
// license that can be found in the LICENSE file.
package main
//go:norace
func Foo(x int) int { // ERROR "can inline Foo with cost .* as: func\(int\) int { return x \* \(x \+ 1\) \* \(x \+ 2\) }$"
return x * (x + 1) * (x + 2)
}
func Bar(x int) int { // ERROR "can inline Bar with cost .* as: func\(int\) int { return x \* \(x \+ 1\) \* \(x \+ 2\) }$"
return x * (x + 1) * (x + 2)
}
var x = 5
//go:noinline Provide a clean, constant reason for not inlining main
func main() { // ERROR "cannot inline main: marked go:noinline$"
println("Foo(", x, ")=", Foo(x)) // ERROR "inlining call to Foo func\(int\) int { return x \* \(x \+ 1\) \* \(x \+ 2\) }$"
println("Bar(", x, ")=", Bar(x)) // ERROR "inlining call to Bar func\(int\) int { return x \* \(x \+ 1\) \* \(x \+ 2\) }$"
}