93b5309f0a
Type inference uses type parameter pointer identity to keep track of the
correspondence between type parameters and type arguments. However, this
technique can misidentify type parameters that are used in explicit type
arguments or function arguments, as in the recursive instantiation
below:
func f[P *Q, Q any](p P, q Q) {
f[P]
}
In this example, the fact that the P used in the instantation f[P] has
the same pointer identity as the P we are trying to solve for via
unification is coincidental: there is nothing special about recursive
calls that should cause them to conflate the identity of type arguments
with type parameters. To put it another way: any such self-recursive
call is equivalent to a mutually recursive call, which does not run into
any problems of type parameter identity. For example, the following code
is equivalent to the code above.
func f[P interface{*Q}, Q any](p P, q Q) {
f2[P]
}
func f2[P interface{*Q}, Q any](p P, q Q) {
f[P]
}
We can turn the first example into the second example by renaming type
parameters in the original signature to give them a new identity. This
CL does this for self-recursive instantiations.
Fixes #51158
Fixes #48656
Updates #48619
Change-Id: I54fe37f2a79c9d98950cf6a3602335db2896dc24
Reviewed-on: https://go-review.googlesource.com/c/go/+/385494
Trust: Robert Findley <rfindley@google.com>
Run-TryBot: Robert Findley <rfindley@google.com>
Reviewed-by: Robert Griesemer <gri@golang.org>
TryBot-Result: Gopher Robot <gobot@golang.org>
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| LICENSE | ||
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| README.md | ||
| SECURITY.md | ||
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