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f1eed92fd0
In some cases the members of the root set from which flood runs themselves escape, without their referents being also tagged as escaping. Fix this by reflooding from those roots whose escape increases, and also enhance the "leak" test to include reachability from a heap-escaped root. Fixes #17318. Change-Id: Ied1e75cee17ede8ca72a8b9302ce8201641ec593 Reviewed-on: https://go-review.googlesource.com/30693 Run-TryBot: David Chase <drchase@google.com> TryBot-Result: Gobot Gobot <gobot@golang.org> Reviewed-by: Russ Cox <rsc@golang.org>
48 lines
1.4 KiB
Go
48 lines
1.4 KiB
Go
// errorcheck -0 -N -m -l
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// Copyright 2016 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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// The escape analyzer needs to run till its root set settles
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// (this is not that often, it turns out).
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// This test is likely to become stale because the leak depends
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// on a spurious-escape bug -- return an interface as a named
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// output parameter appears to cause the called closure to escape,
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// where returning it as a regular type does not.
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package main
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import (
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"fmt"
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)
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type closure func(i, j int) ent
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type ent int
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func (e ent) String() string {
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return fmt.Sprintf("%d", int(e)) // ERROR "ent.String ... argument does not escape$" "int\(e\) escapes to heap$"
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}
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//go:noinline
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func foo(ops closure, j int) (err fmt.Stringer) { // ERROR "leaking param: ops$" "leaking param: ops to result err level=0$"
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enqueue := func(i int) fmt.Stringer { // ERROR "func literal escapes to heap$"
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return ops(i, j) // ERROR "ops\(i, j\) escapes to heap$"
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}
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err = enqueue(4)
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if err != nil {
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return err
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}
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return // return result of enqueue, a fmt.Stringer
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}
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func main() {
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// 3 identical functions, to get different escape behavior.
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f := func(i, j int) ent { // ERROR "func literal escapes to heap$"
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return ent(i + j)
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}
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i := foo(f, 3).(ent)
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fmt.Printf("foo(f,3)=%d\n", int(i)) // ERROR "int\(i\) escapes to heap$" "main ... argument does not escape$"
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}
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