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go/doc/articles/concurrency_patterns.html
Andrew Gerrand d353d43d36 doc: fix typo in Concurrency Patterns article
Fixes #3178.

R=golang-dev, iant
CC=golang-dev
https://golang.org/cl/6506064
2012-09-04 15:28:09 +10:00

80 lines
3.1 KiB
HTML

<!--{
"Title": "Go Concurrency Patterns: Timing out, moving on",
"Template": true
}-->
<p>
Concurrent programming has its own idioms. A good example is timeouts. Although
Go's channels do not support them directly, they are easy to implement. Say we
want to receive from the channel <code>ch</code>, but want to wait at most one
second for the value to arrive. We would start by creating a signalling channel
and launching a goroutine that sleeps before sending on the channel:
</p>
{{code "/doc/progs/timeout1.go" `/timeout :=/` `/STOP/`}}
<p>
We can then use a <code>select</code> statement to receive from either
<code>ch</code> or <code>timeout</code>. If nothing arrives on <code>ch</code>
after one second, the timeout case is selected and the attempt to read from
<code>ch</code> is abandoned.
</p>
{{code "/doc/progs/timeout1.go" `/select {/` `/STOP/`}}
<p>
The <code>timeout</code> channel is buffered with space for 1 value, allowing
the timeout goroutine to send to the channel and then exit. The goroutine
doesn't know (or care) whether the value is received. This means the goroutine
won't hang around forever if the <code>ch</code> receive happens before the
timeout is reached. The <code>timeout</code> channel will eventually be
deallocated by the garbage collector.
</p>
<p>
(In this example we used <code>time.Sleep</code> to demonstrate the mechanics
of goroutines and channels. In real programs you should use <code>
<a href="/pkg/time/#After">time.After</a></code>, a function that returns
a channel and sends on that channel after the specified duration.)
</p>
<p>
Let's look at another variation of this pattern. In this example we have a
program that reads from multiple replicated databases simultaneously. The
program needs only one of the answers, and it should accept the answer that
arrives first.
</p>
<p>
The function <code>Query</code> takes a slice of database connections and a
<code>query</code> string. It queries each of the databases in parallel and
returns the first response it receives:
</p>
{{code "/doc/progs/timeout2.go" `/func Query/` `/STOP/`}}
<p>
In this example, the closure does a non-blocking send, which it achieves by
using the send operation in <code>select</code> statement with a
<code>default</code> case. If the send cannot go through immediately the
default case will be selected. Making the send non-blocking guarantees that
none of the goroutines launched in the loop will hang around. However, if the
result arrives before the main function has made it to the receive, the send
could fail since no one is ready.
</p>
<p>
This problem is a textbook example of what is known as a
<a href="https://en.wikipedia.org/wiki/Race_condition">race condition</a>, but
the fix is trivial. We just make sure to buffer the channel <code>ch</code> (by
adding the buffer length as the second argument to <a href="/pkg/builtin/#make">make</a>),
guaranteeing that the first send has a place to put the value. This ensures the
send will always succeed, and the first value to arrive will be retrieved
regardless of the order of execution.
</p>
<p>
These two examples demonstrate the simplicity with which Go can express complex
interactions between goroutines.
</p>