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https://github.com/golang/go
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4a54ec1d38
There is no reason for these functions to live on the view. They make more sense as unexported functions in internal/lsp/source. Initially, I had to propagate contexts through a lot of functions in internal/lsp/source, but instead I removed the unused contexts forom snapshot.GetFile. Change-Id: I8323419d0356feb2010091fe8d3ed35e511f801a Reviewed-on: https://go-review.googlesource.com/c/tools/+/214384 Run-TryBot: Rebecca Stambler <rstambler@golang.org> TryBot-Result: Gobot Gobot <gobot@golang.org> Reviewed-by: Heschi Kreinick <heschi@google.com>
38 lines
1.1 KiB
Go
38 lines
1.1 KiB
Go
package lsp
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import (
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"context"
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"golang.org/x/tools/internal/lsp/protocol"
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"golang.org/x/tools/internal/lsp/source"
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"golang.org/x/tools/internal/span"
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errors "golang.org/x/xerrors"
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)
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func (s *Server) executeCommand(ctx context.Context, params *protocol.ExecuteCommandParams) (interface{}, error) {
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switch params.Command {
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case "tidy":
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if len(params.Arguments) == 0 || len(params.Arguments) > 1 {
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return nil, errors.Errorf("expected one file URI for call to `go mod tidy`, got %v", params.Arguments)
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}
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// Confirm that this action is being taken on a go.mod file.
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uri := span.NewURI(params.Arguments[0].(string))
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view, err := s.session.ViewOf(uri)
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if err != nil {
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return nil, err
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}
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fh, err := view.Snapshot().GetFile(uri)
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if err != nil {
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return nil, err
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}
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if fh.Identity().Kind != source.Mod {
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return nil, errors.Errorf("%s is not a mod file", uri)
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}
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// Run go.mod tidy on the view.
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if _, err := source.InvokeGo(ctx, view.Folder().Filename(), view.Config(ctx).Env, "mod", "tidy"); err != nil {
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return nil, err
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}
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}
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return nil, nil
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}
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