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go/test/fixedbugs/issue14164.dir/a.go
Robert Griesemer d37d76af43 cmd/compile: fix parsing of inlined interface types with unexported methods
Fixes #14164.

Change-Id: Ib1d1d29674c99cf88e0ae12724823a31f5dbb95c
Reviewed-on: https://go-review.googlesource.com/19087
Run-TryBot: Robert Griesemer <gri@golang.org>
TryBot-Result: Gobot Gobot <gobot@golang.org>
Reviewed-by: Russ Cox <rsc@golang.org>
2016-02-01 20:29:19 +00:00

48 lines
1.1 KiB
Go

// Copyright 2016 The Go Authors. All rights reserved.
// Use of this source code is governed by a BSD-style
// license that can be found in the LICENSE file.
package a
// F is an exported function, small enough to be inlined.
// It defines a local interface with an unexported method
// f, which will appear with a package-qualified method
// name in the export data.
func F(x interface{}) bool {
_, ok := x.(interface {
f()
})
return ok
}
// Like F but with the unexported interface method f
// defined via an embedded interface t. The compiler
// always flattens embedded interfaces so there should
// be no difference between F and G. Alas, currently
// G is not inlineable (at least via export data), so
// the issue is moot, here.
func G(x interface{}) bool {
type t0 interface {
f()
}
_, ok := x.(interface {
t0
})
return ok
}
// Like G but now the embedded interface is declared
// at package level. This function is inlineable via
// export data. The export data representation is like
// for F.
func H(x interface{}) bool {
_, ok := x.(interface {
t1
})
return ok
}
type t1 interface {
f()
}