1
0
mirror of https://github.com/golang/go synced 2024-11-13 19:20:31 -07:00
go/test/fixedbugs/issue15175.go
Emmanuel Odeke 53fd522c0d all: make copyright headers consistent with one space after period
Follows suit with https://go-review.googlesource.com/#/c/20111.

Generated by running
$ grep -R 'Go Authors.  All' * | cut -d":" -f1 | while read F;do perl -pi -e 's/Go
Authors.  All/Go Authors. All/g' $F;done

The code in cmd/internal/unvendor wasn't changed.

Fixes #15213

Change-Id: I4f235cee0a62ec435f9e8540a1ec08ae03b1a75f
Reviewed-on: https://go-review.googlesource.com/21819
Reviewed-by: Ian Lance Taylor <iant@golang.org>
Run-TryBot: Ian Lance Taylor <iant@golang.org>
TryBot-Result: Gobot Gobot <gobot@golang.org>
2016-05-02 13:43:18 +00:00

67 lines
1.8 KiB
Go

// run
// Copyright 2016 The Go Authors. All rights reserved.
// Use of this source code is governed by a BSD-style
// license that can be found in the LICENSE file.
// Make sure unsigned shift results get sign-extended correctly.
package main
import "fmt"
func main() {
failed := false
a6 := uint8(253)
if got := a6 >> 0; got != 253 {
fmt.Printf("uint8(253)>>0 = %v, wanted 253\n", got)
failed = true
}
if got := f1(0, 2, 1, 0, 0, 1, true); got != 255 {
fmt.Printf("f1(...) = %v, wanted 255\n", got)
failed = true
}
if got := f2(1); got != 242 {
fmt.Printf("f2(...) = %v, wanted 242\n", got)
failed = true
}
if got := f3(false, 0, 0); got != 254 {
fmt.Printf("f3(...) = %v, wanted 254\n", got)
failed = true
}
if failed {
panic("bad")
}
}
func f1(a1 uint, a2 int8, a3 int8, a4 int8, a5 uint8, a6 int, a7 bool) uint8 {
a5--
a4 += (a2 << a1 << 2) | (a4 ^ a4<<(a1&a1)) - a3 // int8
a6 -= a6 >> (2 + uint32(a2)>>3) // int
a1 += a1 // uint
a3 *= a4 << (a1 | a1) << (uint16(3) >> 2 & (1 - 0) & (uint16(1) << a5 << 3)) // int8
a7 = a7 || ((a2 == a4) || (a7 && a7) || ((a5 == a5) || (a7 || a7))) // bool
return a5 >> a1
}
func f2(a1 uint8) uint8 {
a1--
a1--
a1 -= a1 + (a1 << 1) - (a1*a1*a1)<<(2-0+(3|3)-1) // uint8
v1 := 0 * ((2 * 1) ^ 1) & ((uint(0) >> a1) + (2+0)*(uint(2)+0)) // uint
_ = v1
return a1 >> (((2 ^ 2) >> (v1 | 2)) + 0)
}
func f3(a1 bool, a2 uint, a3 int64) uint8 {
a3--
v1 := 1 & (2 & 1 * (1 ^ 2) & (uint8(3*1) >> 0)) // uint8
_ = v1
v1 += v1 - (v1 >> a2) + (v1 << (a2 ^ a2) & v1) // uint8
v1 *= v1 // uint8
a3--
v1 += v1 & v1 // uint8
v1--
v1 = ((v1 << 0) | v1>>0) + v1 // uint8
return v1 >> 0
}