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64a767472a
I wasn't sure if we should just manually construct the URI here or use the URL unescaping function. Let me know which you think is best. Updates golang/go#34270 Change-Id: Idb48fc2650d39f3e54cac141a70f356c31e303ad Reviewed-on: https://go-review.googlesource.com/c/tools/+/195618 Run-TryBot: Rebecca Stambler <rstambler@golang.org> Reviewed-by: Ian Cottrell <iancottrell@google.com>
52 lines
1.4 KiB
Go
52 lines
1.4 KiB
Go
// Copyright 2019 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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package span_test
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import (
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"path/filepath"
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"testing"
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"golang.org/x/tools/internal/span"
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)
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// TestURI tests the conversion between URIs and filenames. The test cases
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// include Windows-style URIs and filepaths, but we avoid having OS-specific
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// tests by using only forward slashes, assuming that the standard library
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// functions filepath.ToSlash and filepath.FromSlash do not need testing.
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func TestURI(t *testing.T) {
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for _, test := range []string{
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``,
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`C:/Windows/System32`,
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`C:/Go/src/bob.go`,
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`c:/Go/src/bob.go`,
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`/path/to/dir`,
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`/a/b/c/src/bob.go`,
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`c:/Go/src/bob george/george/george.go`,
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} {
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testPath := filepath.FromSlash(test)
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expectPath := testPath
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if len(test) > 0 && test[0] == '/' {
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if abs, err := filepath.Abs(expectPath); err == nil {
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expectPath = abs
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}
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}
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expectURI := filepath.ToSlash(expectPath)
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if len(expectURI) > 0 {
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if expectURI[0] != '/' {
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expectURI = "/" + expectURI
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}
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expectURI = "file://" + expectURI
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}
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uri := span.FileURI(testPath)
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if expectURI != string(uri) {
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t.Errorf("ToURI: expected %s, got %s", expectURI, uri)
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}
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filename := uri.Filename()
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if expectPath != filename {
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t.Errorf("Filename: expected %s, got %s", expectPath, filename)
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}
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}
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}
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