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rand: add explicit Int31n to avoid 64-bit divide on 32-bit machines
use Int31n in Intn when possible. Fixes #390. (using 8g) Intn1000 50000000 38 ns/op Int31n1000 50000000 39 ns/op Int63n1000 20000000 114 ns/op R=r CC=golang-dev, skybrian https://golang.org/cl/180054
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@ -62,10 +62,25 @@ func (r *Rand) Int63n(n int64) int64 {
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}
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}
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// Int31n returns, as an int32, a non-negative pseudo-random number in [0,n).
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// Int31n returns, as an int32, a non-negative pseudo-random number in [0,n).
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func (r *Rand) Int31n(n int32) int32 { return int32(r.Int63n(int64(n))) }
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func (r *Rand) Int31n(n int32) int32 {
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if n <= 0 {
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return 0
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}
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max := int32((1 << 31) - 1 - (1<<31)%uint32(n))
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v := r.Int31()
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for v > max {
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v = r.Int31()
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}
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return v % n
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}
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// Intn returns, as an int, a non-negative pseudo-random number in [0,n).
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// Intn returns, as an int, a non-negative pseudo-random number in [0,n).
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func (r *Rand) Intn(n int) int { return int(r.Int63n(int64(n))) }
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func (r *Rand) Intn(n int) int {
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if n <= 1<<31-1 {
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return int(r.Int31n(int32(n)))
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}
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return int(r.Int63n(int64(n)))
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}
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// Float64 returns, as a float64, a pseudo-random number in [0.0,1.0).
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// Float64 returns, as a float64, a pseudo-random number in [0.0,1.0).
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func (r *Rand) Float64() float64 { return float64(r.Int63()) / (1 << 63) }
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func (r *Rand) Float64() float64 { return float64(r.Int63()) / (1 << 63) }
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@ -327,3 +327,24 @@ func BenchmarkInt63Unthreadsafe(b *testing.B) {
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r.Int63()
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r.Int63()
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}
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}
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}
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}
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func BenchmarkIntn1000(b *testing.B) {
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r := New(NewSource(1))
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for n := b.N; n > 0; n-- {
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r.Intn(1000)
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}
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}
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func BenchmarkInt63n1000(b *testing.B) {
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r := New(NewSource(1))
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for n := b.N; n > 0; n-- {
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r.Int63n(1000)
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}
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}
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func BenchmarkInt31n1000(b *testing.B) {
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r := New(NewSource(1))
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for n := b.N; n > 0; n-- {
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r.Int31n(1000)
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}
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}
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