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regexp: add (*Regexp).Longest
Fixes #3696. R=rsc CC=golang-dev https://golang.org/cl/7133051
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@ -706,3 +706,17 @@ func BenchmarkMatchHard_1K(b *testing.B) { benchmark(b, hard, 1<<10) }
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func BenchmarkMatchHard_32K(b *testing.B) { benchmark(b, hard, 32<<10) }
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func BenchmarkMatchHard_1M(b *testing.B) { benchmark(b, hard, 1<<20) }
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func BenchmarkMatchHard_32M(b *testing.B) { benchmark(b, hard, 32<<20) }
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func TestLongest(t *testing.T) {
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re, err := Compile(`a(|b)`)
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if err != nil {
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t.Fatal(err)
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}
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if g, w := re.FindString("ab"), "a"; g != w {
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t.Errorf("first match was %q, want %q", g, w)
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}
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re.Longest()
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if g, w := re.FindString("ab"), "ab"; g != w {
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t.Errorf("longest match was %q, want %q", g, w)
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}
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}
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@ -130,6 +130,14 @@ func CompilePOSIX(expr string) (*Regexp, error) {
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return compile(expr, syntax.POSIX, true)
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}
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// Longest sets the match semantics of the regexp to leftmost-longest.
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// That is, when matching against text, the regexp returns a match that
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// begins as early as possible in the input (leftmost), and among those
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// it chooses a match that is as long as possible.
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func (re *Regexp) Longest() {
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re.longest = true
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}
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func compile(expr string, mode syntax.Flags, longest bool) (*Regexp, error) {
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re, err := syntax.Parse(expr, mode)
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if err != nil {
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