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make sure errchk only prints BUG once.
using a variable is not sufficient, because sometimes bug() is called from a subshell. R=iant DELTA=7 (2 added, 1 deleted, 4 changed) OCL=18092 CL=18145
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7112dc1db7
commit
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11
test/errchk
11
test/errchk
@ -29,9 +29,11 @@ TMPERR=/tmp/errchk-err-$$
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TMPALL=/tmp/errchk-all-$$
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TMPTMP=/tmp/errchk-tmp-$$
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TMPSTAT=/tmp/errchk-stat-$$
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rm -f $TMPOUT $TMPERR $TMPALL $TMPTMP $TMPSTAT
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TMPBUG=/tmp/errchk-bug-$$
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trap "rm -f $TMPOUT $TMPERR $TMPALL $TMPTMP $TMPSTAT" 0 1 2 3 14 15
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rm -f $TMPOUT $TMPERR $TMPALL $TMPTMP $TMPSTAT $TMPBUG
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trap "rm -f $TMPOUT $TMPERR $TMPALL $TMPTMP $TMPSTAT $TMPBUG" 0 1 2 3 14 15
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if $* >$TMPOUT 2>$TMPERR; then
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echo 1>&2 "BUG: errchk: command succeeded unexpectedly: " "$@"
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@ -43,12 +45,11 @@ fi
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cat $TMPOUT $TMPERR | grep -v '^ ' > $TMPALL
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didbug=false
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bug() {
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if ! $didbug
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if ! test -f $TMPBUG
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then
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echo 1>&2 -n BUG: ''
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didbug=true
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echo >$TMPBUG
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fi
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}
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