mirror of
https://github.com/golang/go
synced 2024-11-23 07:00:05 -07:00
math/big: move division into natdiv.go
Code moved and functions reordered to be in a consistent top-down dependency order, but otherwise unchanged. First step toward commenting division algorithms. Change-Id: Ib5e604fb5b2867edff3a228ba4e57b5cb32c4137 Reviewed-on: https://go-review.googlesource.com/c/go/+/321077 Trust: Russ Cox <rsc@golang.org> Trust: Katie Hockman <katie@golang.org> Trust: Robert Griesemer <gri@golang.org> Run-TryBot: Russ Cox <rsc@golang.org> TryBot-Result: Go Bot <gobot@golang.org> Reviewed-by: Katie Hockman <katie@golang.org> Reviewed-by: Robert Griesemer <gri@golang.org>
This commit is contained in:
Russ Cox
parent
d050238bb6
commit
e4615ad74d
@ -267,20 +267,6 @@ func divWW(x1, x0, y, m Word) (q, r Word) {
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return Word(qq), Word(r0 >> s)
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}
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func divWVW(z []Word, xn Word, x []Word, y Word) (r Word) {
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r = xn
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if len(x) == 1 {
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qq, rr := bits.Div(uint(r), uint(x[0]), uint(y))
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z[0] = Word(qq)
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return Word(rr)
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}
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rec := reciprocalWord(y)
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for i := len(z) - 1; i >= 0; i-- {
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z[i], r = divWW(r, x[i], y, rec)
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}
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return r
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}
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// reciprocalWord return the reciprocal of the divisor. rec = floor(( _B^2 - 1 ) / u - _B). u = d1 << nlz(d1).
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func reciprocalWord(d1 Word) Word {
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u := uint(d1 << nlz(d1))
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@ -631,48 +631,6 @@ func (z nat) mulRange(a, b uint64) nat {
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return z.mul(nat(nil).mulRange(a, m), nat(nil).mulRange(m+1, b))
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}
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// q = (x-r)/y, with 0 <= r < y
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func (z nat) divW(x nat, y Word) (q nat, r Word) {
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m := len(x)
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switch {
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case y == 0:
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panic("division by zero")
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case y == 1:
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q = z.set(x) // result is x
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return
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case m == 0:
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q = z[:0] // result is 0
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return
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}
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// m > 0
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z = z.make(m)
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r = divWVW(z, 0, x, y)
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q = z.norm()
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return
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}
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func (z nat) div(z2, u, v nat) (q, r nat) {
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if len(v) == 0 {
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panic("division by zero")
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}
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if u.cmp(v) < 0 {
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q = z[:0]
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r = z2.set(u)
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return
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}
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if len(v) == 1 {
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var r2 Word
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q, r2 = z.divW(u, v[0])
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r = z2.setWord(r2)
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return
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}
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q, r = z.divLarge(z2, u, v)
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return
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}
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// getNat returns a *nat of len n. The contents may not be zero.
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// The pool holds *nat to avoid allocation when converting to interface{}.
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func getNat(n int) *nat {
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@ -693,276 +651,6 @@ func putNat(x *nat) {
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var natPool sync.Pool
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// q = (uIn-r)/vIn, with 0 <= r < vIn
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// Uses z as storage for q, and u as storage for r if possible.
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// See Knuth, Volume 2, section 4.3.1, Algorithm D.
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// Preconditions:
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// len(vIn) >= 2
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// len(uIn) >= len(vIn)
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// u must not alias z
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func (z nat) divLarge(u, uIn, vIn nat) (q, r nat) {
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n := len(vIn)
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m := len(uIn) - n
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// D1.
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shift := nlz(vIn[n-1])
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// do not modify vIn, it may be used by another goroutine simultaneously
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vp := getNat(n)
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v := *vp
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shlVU(v, vIn, shift)
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// u may safely alias uIn or vIn, the value of uIn is used to set u and vIn was already used
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u = u.make(len(uIn) + 1)
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u[len(uIn)] = shlVU(u[0:len(uIn)], uIn, shift)
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// z may safely alias uIn or vIn, both values were used already
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if alias(z, u) {
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z = nil // z is an alias for u - cannot reuse
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}
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q = z.make(m + 1)
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if n < divRecursiveThreshold {
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q.divBasic(u, v)
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} else {
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q.divRecursive(u, v)
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}
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putNat(vp)
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q = q.norm()
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shrVU(u, u, shift)
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r = u.norm()
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return q, r
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}
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// divBasic performs word-by-word division of u by v.
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// The quotient is written in pre-allocated q.
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// The remainder overwrites input u.
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//
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// Precondition:
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// - q is large enough to hold the quotient u / v
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// which has a maximum length of len(u)-len(v)+1.
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func (q nat) divBasic(u, v nat) {
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n := len(v)
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m := len(u) - n
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qhatvp := getNat(n + 1)
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qhatv := *qhatvp
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// D2.
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vn1 := v[n-1]
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rec := reciprocalWord(vn1)
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for j := m; j >= 0; j-- {
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// D3.
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qhat := Word(_M)
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var ujn Word
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if j+n < len(u) {
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ujn = u[j+n]
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}
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if ujn != vn1 {
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var rhat Word
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qhat, rhat = divWW(ujn, u[j+n-1], vn1, rec)
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// x1 | x2 = q̂v_{n-2}
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vn2 := v[n-2]
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x1, x2 := mulWW(qhat, vn2)
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// test if q̂v_{n-2} > br̂ + u_{j+n-2}
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ujn2 := u[j+n-2]
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for greaterThan(x1, x2, rhat, ujn2) {
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qhat--
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prevRhat := rhat
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rhat += vn1
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// v[n-1] >= 0, so this tests for overflow.
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if rhat < prevRhat {
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break
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}
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x1, x2 = mulWW(qhat, vn2)
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}
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}
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// D4.
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// Compute the remainder u - (q̂*v) << (_W*j).
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// The subtraction may overflow if q̂ estimate was off by one.
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qhatv[n] = mulAddVWW(qhatv[0:n], v, qhat, 0)
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qhl := len(qhatv)
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if j+qhl > len(u) && qhatv[n] == 0 {
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qhl--
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}
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c := subVV(u[j:j+qhl], u[j:], qhatv)
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if c != 0 {
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c := addVV(u[j:j+n], u[j:], v)
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// If n == qhl, the carry from subVV and the carry from addVV
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// cancel out and don't affect u[j+n].
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if n < qhl {
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u[j+n] += c
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}
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qhat--
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}
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if j == m && m == len(q) && qhat == 0 {
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continue
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}
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q[j] = qhat
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}
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putNat(qhatvp)
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}
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const divRecursiveThreshold = 100
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// divRecursive performs word-by-word division of u by v.
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// The quotient is written in pre-allocated z.
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// The remainder overwrites input u.
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//
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// Precondition:
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// - len(z) >= len(u)-len(v)
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//
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// See Burnikel, Ziegler, "Fast Recursive Division", Algorithm 1 and 2.
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func (z nat) divRecursive(u, v nat) {
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// Recursion depth is less than 2 log2(len(v))
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// Allocate a slice of temporaries to be reused across recursion.
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recDepth := 2 * bits.Len(uint(len(v)))
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// large enough to perform Karatsuba on operands as large as v
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tmp := getNat(3 * len(v))
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temps := make([]*nat, recDepth)
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z.clear()
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z.divRecursiveStep(u, v, 0, tmp, temps)
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for _, n := range temps {
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if n != nil {
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putNat(n)
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}
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}
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putNat(tmp)
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}
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// divRecursiveStep computes the division of u by v.
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// - z must be large enough to hold the quotient
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// - the quotient will overwrite z
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// - the remainder will overwrite u
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func (z nat) divRecursiveStep(u, v nat, depth int, tmp *nat, temps []*nat) {
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u = u.norm()
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v = v.norm()
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if len(u) == 0 {
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z.clear()
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return
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}
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n := len(v)
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if n < divRecursiveThreshold {
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z.divBasic(u, v)
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return
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}
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m := len(u) - n
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if m < 0 {
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return
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}
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// Produce the quotient by blocks of B words.
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// Division by v (length n) is done using a length n/2 division
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// and a length n/2 multiplication for each block. The final
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// complexity is driven by multiplication complexity.
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B := n / 2
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// Allocate a nat for qhat below.
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if temps[depth] == nil {
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temps[depth] = getNat(n)
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} else {
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*temps[depth] = temps[depth].make(B + 1)
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}
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j := m
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for j > B {
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// Divide u[j-B:j+n] by vIn. Keep remainder in u
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// for next block.
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//
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// The following property will be used (Lemma 2):
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// if u = u1 << s + u0
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// v = v1 << s + v0
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// then floor(u1/v1) >= floor(u/v)
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//
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// Moreover, the difference is at most 2 if len(v1) >= len(u/v)
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// We choose s = B-1 since len(v)-s >= B+1 >= len(u/v)
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s := (B - 1)
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// Except for the first step, the top bits are always
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// a division remainder, so the quotient length is <= n.
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uu := u[j-B:]
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qhat := *temps[depth]
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qhat.clear()
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qhat.divRecursiveStep(uu[s:B+n], v[s:], depth+1, tmp, temps)
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qhat = qhat.norm()
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// Adjust the quotient:
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// u = u_h << s + u_l
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// v = v_h << s + v_l
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// u_h = q̂ v_h + rh
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// u = q̂ (v - v_l) + rh << s + u_l
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// After the above step, u contains a remainder:
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// u = rh << s + u_l
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// and we need to subtract q̂ v_l
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//
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// But it may be a bit too large, in which case q̂ needs to be smaller.
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qhatv := tmp.make(3 * n)
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qhatv.clear()
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qhatv = qhatv.mul(qhat, v[:s])
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for i := 0; i < 2; i++ {
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e := qhatv.cmp(uu.norm())
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if e <= 0 {
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break
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}
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subVW(qhat, qhat, 1)
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c := subVV(qhatv[:s], qhatv[:s], v[:s])
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if len(qhatv) > s {
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subVW(qhatv[s:], qhatv[s:], c)
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}
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addAt(uu[s:], v[s:], 0)
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}
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if qhatv.cmp(uu.norm()) > 0 {
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panic("impossible")
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}
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c := subVV(uu[:len(qhatv)], uu[:len(qhatv)], qhatv)
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if c > 0 {
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subVW(uu[len(qhatv):], uu[len(qhatv):], c)
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}
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addAt(z, qhat, j-B)
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j -= B
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}
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// Now u < (v<<B), compute lower bits in the same way.
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// Choose shift = B-1 again.
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s := B - 1
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qhat := *temps[depth]
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qhat.clear()
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qhat.divRecursiveStep(u[s:].norm(), v[s:], depth+1, tmp, temps)
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qhat = qhat.norm()
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qhatv := tmp.make(3 * n)
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qhatv.clear()
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qhatv = qhatv.mul(qhat, v[:s])
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// Set the correct remainder as before.
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for i := 0; i < 2; i++ {
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if e := qhatv.cmp(u.norm()); e > 0 {
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subVW(qhat, qhat, 1)
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c := subVV(qhatv[:s], qhatv[:s], v[:s])
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if len(qhatv) > s {
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subVW(qhatv[s:], qhatv[s:], c)
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}
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addAt(u[s:], v[s:], 0)
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}
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}
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if qhatv.cmp(u.norm()) > 0 {
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panic("impossible")
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}
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c := subVV(u[0:len(qhatv)], u[0:len(qhatv)], qhatv)
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if c > 0 {
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c = subVW(u[len(qhatv):], u[len(qhatv):], c)
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}
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if c > 0 {
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panic("impossible")
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}
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// Done!
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addAt(z, qhat.norm(), 0)
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}
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// Length of x in bits. x must be normalized.
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func (x nat) bitLen() int {
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if i := len(x) - 1; i >= 0 {
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@ -1170,19 +858,6 @@ func (z nat) xor(x, y nat) nat {
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return z.norm()
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}
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// greaterThan reports whether (x1<<_W + x2) > (y1<<_W + y2)
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func greaterThan(x1, x2, y1, y2 Word) bool {
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return x1 > y1 || x1 == y1 && x2 > y2
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}
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// modW returns x % d.
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func (x nat) modW(d Word) (r Word) {
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// TODO(agl): we don't actually need to store the q value.
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var q nat
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q = q.make(len(x))
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return divWVW(q, 0, x, d)
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}
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// random creates a random integer in [0..limit), using the space in z if
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// possible. n is the bit length of limit.
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func (z nat) random(rand *rand.Rand, limit nat, n int) nat {
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346
src/math/big/natdiv.go
Normal file
346
src/math/big/natdiv.go
Normal file
@ -0,0 +1,346 @@
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// Copyright 2009 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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package big
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import "math/bits"
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func (z nat) div(z2, u, v nat) (q, r nat) {
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if len(v) == 0 {
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panic("division by zero")
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}
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if u.cmp(v) < 0 {
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q = z[:0]
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r = z2.set(u)
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return
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}
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if len(v) == 1 {
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var r2 Word
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q, r2 = z.divW(u, v[0])
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r = z2.setWord(r2)
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return
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}
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q, r = z.divLarge(z2, u, v)
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return
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}
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// q = (x-r)/y, with 0 <= r < y
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func (z nat) divW(x nat, y Word) (q nat, r Word) {
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m := len(x)
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switch {
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case y == 0:
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panic("division by zero")
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case y == 1:
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q = z.set(x) // result is x
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return
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case m == 0:
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q = z[:0] // result is 0
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return
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}
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// m > 0
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z = z.make(m)
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r = divWVW(z, 0, x, y)
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q = z.norm()
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return
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}
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// modW returns x % d.
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func (x nat) modW(d Word) (r Word) {
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// TODO(agl): we don't actually need to store the q value.
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var q nat
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q = q.make(len(x))
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return divWVW(q, 0, x, d)
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}
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func divWVW(z []Word, xn Word, x []Word, y Word) (r Word) {
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r = xn
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if len(x) == 1 {
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qq, rr := bits.Div(uint(r), uint(x[0]), uint(y))
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z[0] = Word(qq)
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return Word(rr)
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}
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rec := reciprocalWord(y)
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for i := len(z) - 1; i >= 0; i-- {
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z[i], r = divWW(r, x[i], y, rec)
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}
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return r
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}
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// q = (uIn-r)/vIn, with 0 <= r < vIn
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// Uses z as storage for q, and u as storage for r if possible.
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// See Knuth, Volume 2, section 4.3.1, Algorithm D.
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// Preconditions:
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// len(vIn) >= 2
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// len(uIn) >= len(vIn)
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// u must not alias z
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func (z nat) divLarge(u, uIn, vIn nat) (q, r nat) {
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n := len(vIn)
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m := len(uIn) - n
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// D1.
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shift := nlz(vIn[n-1])
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// do not modify vIn, it may be used by another goroutine simultaneously
|
||||
vp := getNat(n)
|
||||
v := *vp
|
||||
shlVU(v, vIn, shift)
|
||||
|
||||
// u may safely alias uIn or vIn, the value of uIn is used to set u and vIn was already used
|
||||
u = u.make(len(uIn) + 1)
|
||||
u[len(uIn)] = shlVU(u[0:len(uIn)], uIn, shift)
|
||||
|
||||
// z may safely alias uIn or vIn, both values were used already
|
||||
if alias(z, u) {
|
||||
z = nil // z is an alias for u - cannot reuse
|
||||
}
|
||||
q = z.make(m + 1)
|
||||
|
||||
if n < divRecursiveThreshold {
|
||||
q.divBasic(u, v)
|
||||
} else {
|
||||
q.divRecursive(u, v)
|
||||
}
|
||||
putNat(vp)
|
||||
|
||||
q = q.norm()
|
||||
shrVU(u, u, shift)
|
||||
r = u.norm()
|
||||
|
||||
return q, r
|
||||
}
|
||||
|
||||
// divBasic performs word-by-word division of u by v.
|
||||
// The quotient is written in pre-allocated q.
|
||||
// The remainder overwrites input u.
|
||||
//
|
||||
// Precondition:
|
||||
// - q is large enough to hold the quotient u / v
|
||||
// which has a maximum length of len(u)-len(v)+1.
|
||||
func (q nat) divBasic(u, v nat) {
|
||||
n := len(v)
|
||||
m := len(u) - n
|
||||
|
||||
qhatvp := getNat(n + 1)
|
||||
qhatv := *qhatvp
|
||||
|
||||
// D2.
|
||||
vn1 := v[n-1]
|
||||
rec := reciprocalWord(vn1)
|
||||
for j := m; j >= 0; j-- {
|
||||
// D3.
|
||||
qhat := Word(_M)
|
||||
var ujn Word
|
||||
if j+n < len(u) {
|
||||
ujn = u[j+n]
|
||||
}
|
||||
if ujn != vn1 {
|
||||
var rhat Word
|
||||
qhat, rhat = divWW(ujn, u[j+n-1], vn1, rec)
|
||||
|
||||
// x1 | x2 = q̂v_{n-2}
|
||||
vn2 := v[n-2]
|
||||
x1, x2 := mulWW(qhat, vn2)
|
||||
// test if q̂v_{n-2} > br̂ + u_{j+n-2}
|
||||
ujn2 := u[j+n-2]
|
||||
for greaterThan(x1, x2, rhat, ujn2) {
|
||||
qhat--
|
||||
prevRhat := rhat
|
||||
rhat += vn1
|
||||
// v[n-1] >= 0, so this tests for overflow.
|
||||
if rhat < prevRhat {
|
||||
break
|
||||
}
|
||||
x1, x2 = mulWW(qhat, vn2)
|
||||
}
|
||||
}
|
||||
|
||||
// D4.
|
||||
// Compute the remainder u - (q̂*v) << (_W*j).
|
||||
// The subtraction may overflow if q̂ estimate was off by one.
|
||||
qhatv[n] = mulAddVWW(qhatv[0:n], v, qhat, 0)
|
||||
qhl := len(qhatv)
|
||||
if j+qhl > len(u) && qhatv[n] == 0 {
|
||||
qhl--
|
||||
}
|
||||
c := subVV(u[j:j+qhl], u[j:], qhatv)
|
||||
if c != 0 {
|
||||
c := addVV(u[j:j+n], u[j:], v)
|
||||
// If n == qhl, the carry from subVV and the carry from addVV
|
||||
// cancel out and don't affect u[j+n].
|
||||
if n < qhl {
|
||||
u[j+n] += c
|
||||
}
|
||||
qhat--
|
||||
}
|
||||
|
||||
if j == m && m == len(q) && qhat == 0 {
|
||||
continue
|
||||
}
|
||||
q[j] = qhat
|
||||
}
|
||||
|
||||
putNat(qhatvp)
|
||||
}
|
||||
|
||||
// greaterThan reports whether (x1<<_W + x2) > (y1<<_W + y2)
|
||||
func greaterThan(x1, x2, y1, y2 Word) bool {
|
||||
return x1 > y1 || x1 == y1 && x2 > y2
|
||||
}
|
||||
|
||||
const divRecursiveThreshold = 100
|
||||
|
||||
// divRecursive performs word-by-word division of u by v.
|
||||
// The quotient is written in pre-allocated z.
|
||||
// The remainder overwrites input u.
|
||||
//
|
||||
// Precondition:
|
||||
// - len(z) >= len(u)-len(v)
|
||||
//
|
||||
// See Burnikel, Ziegler, "Fast Recursive Division", Algorithm 1 and 2.
|
||||
func (z nat) divRecursive(u, v nat) {
|
||||
// Recursion depth is less than 2 log2(len(v))
|
||||
// Allocate a slice of temporaries to be reused across recursion.
|
||||
recDepth := 2 * bits.Len(uint(len(v)))
|
||||
// large enough to perform Karatsuba on operands as large as v
|
||||
tmp := getNat(3 * len(v))
|
||||
temps := make([]*nat, recDepth)
|
||||
z.clear()
|
||||
z.divRecursiveStep(u, v, 0, tmp, temps)
|
||||
for _, n := range temps {
|
||||
if n != nil {
|
||||
putNat(n)
|
||||
}
|
||||
}
|
||||
putNat(tmp)
|
||||
}
|
||||
|
||||
// divRecursiveStep computes the division of u by v.
|
||||
// - z must be large enough to hold the quotient
|
||||
// - the quotient will overwrite z
|
||||
// - the remainder will overwrite u
|
||||
func (z nat) divRecursiveStep(u, v nat, depth int, tmp *nat, temps []*nat) {
|
||||
u = u.norm()
|
||||
v = v.norm()
|
||||
|
||||
if len(u) == 0 {
|
||||
z.clear()
|
||||
return
|
||||
}
|
||||
n := len(v)
|
||||
if n < divRecursiveThreshold {
|
||||
z.divBasic(u, v)
|
||||
return
|
||||
}
|
||||
m := len(u) - n
|
||||
if m < 0 {
|
||||
return
|
||||
}
|
||||
|
||||
// Produce the quotient by blocks of B words.
|
||||
// Division by v (length n) is done using a length n/2 division
|
||||
// and a length n/2 multiplication for each block. The final
|
||||
// complexity is driven by multiplication complexity.
|
||||
B := n / 2
|
||||
|
||||
// Allocate a nat for qhat below.
|
||||
if temps[depth] == nil {
|
||||
temps[depth] = getNat(n)
|
||||
} else {
|
||||
*temps[depth] = temps[depth].make(B + 1)
|
||||
}
|
||||
|
||||
j := m
|
||||
for j > B {
|
||||
// Divide u[j-B:j+n] by vIn. Keep remainder in u
|
||||
// for next block.
|
||||
//
|
||||
// The following property will be used (Lemma 2):
|
||||
// if u = u1 << s + u0
|
||||
// v = v1 << s + v0
|
||||
// then floor(u1/v1) >= floor(u/v)
|
||||
//
|
||||
// Moreover, the difference is at most 2 if len(v1) >= len(u/v)
|
||||
// We choose s = B-1 since len(v)-s >= B+1 >= len(u/v)
|
||||
s := (B - 1)
|
||||
// Except for the first step, the top bits are always
|
||||
// a division remainder, so the quotient length is <= n.
|
||||
uu := u[j-B:]
|
||||
|
||||
qhat := *temps[depth]
|
||||
qhat.clear()
|
||||
qhat.divRecursiveStep(uu[s:B+n], v[s:], depth+1, tmp, temps)
|
||||
qhat = qhat.norm()
|
||||
// Adjust the quotient:
|
||||
// u = u_h << s + u_l
|
||||
// v = v_h << s + v_l
|
||||
// u_h = q̂ v_h + rh
|
||||
// u = q̂ (v - v_l) + rh << s + u_l
|
||||
// After the above step, u contains a remainder:
|
||||
// u = rh << s + u_l
|
||||
// and we need to subtract q̂ v_l
|
||||
//
|
||||
// But it may be a bit too large, in which case q̂ needs to be smaller.
|
||||
qhatv := tmp.make(3 * n)
|
||||
qhatv.clear()
|
||||
qhatv = qhatv.mul(qhat, v[:s])
|
||||
for i := 0; i < 2; i++ {
|
||||
e := qhatv.cmp(uu.norm())
|
||||
if e <= 0 {
|
||||
break
|
||||
}
|
||||
subVW(qhat, qhat, 1)
|
||||
c := subVV(qhatv[:s], qhatv[:s], v[:s])
|
||||
if len(qhatv) > s {
|
||||
subVW(qhatv[s:], qhatv[s:], c)
|
||||
}
|
||||
addAt(uu[s:], v[s:], 0)
|
||||
}
|
||||
if qhatv.cmp(uu.norm()) > 0 {
|
||||
panic("impossible")
|
||||
}
|
||||
c := subVV(uu[:len(qhatv)], uu[:len(qhatv)], qhatv)
|
||||
if c > 0 {
|
||||
subVW(uu[len(qhatv):], uu[len(qhatv):], c)
|
||||
}
|
||||
addAt(z, qhat, j-B)
|
||||
j -= B
|
||||
}
|
||||
|
||||
// Now u < (v<<B), compute lower bits in the same way.
|
||||
// Choose shift = B-1 again.
|
||||
s := B - 1
|
||||
qhat := *temps[depth]
|
||||
qhat.clear()
|
||||
qhat.divRecursiveStep(u[s:].norm(), v[s:], depth+1, tmp, temps)
|
||||
qhat = qhat.norm()
|
||||
qhatv := tmp.make(3 * n)
|
||||
qhatv.clear()
|
||||
qhatv = qhatv.mul(qhat, v[:s])
|
||||
// Set the correct remainder as before.
|
||||
for i := 0; i < 2; i++ {
|
||||
if e := qhatv.cmp(u.norm()); e > 0 {
|
||||
subVW(qhat, qhat, 1)
|
||||
c := subVV(qhatv[:s], qhatv[:s], v[:s])
|
||||
if len(qhatv) > s {
|
||||
subVW(qhatv[s:], qhatv[s:], c)
|
||||
}
|
||||
addAt(u[s:], v[s:], 0)
|
||||
}
|
||||
}
|
||||
if qhatv.cmp(u.norm()) > 0 {
|
||||
panic("impossible")
|
||||
}
|
||||
c := subVV(u[0:len(qhatv)], u[0:len(qhatv)], qhatv)
|
||||
if c > 0 {
|
||||
c = subVW(u[len(qhatv):], u[len(qhatv):], c)
|
||||
}
|
||||
if c > 0 {
|
||||
panic("impossible")
|
||||
}
|
||||
|
||||
// Done!
|
||||
addAt(z, qhat.norm(), 0)
|
||||
}
|
||||
Loading…
Reference in New Issue
Block a user