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gc: use inferred type rather than original one when reporting non-assignability.

Fixes #2451

R=rsc, bradfitz
CC=golang-dev
https://golang.org/cl/5372105
This commit is contained in:
Luuk van Dijk 2011-12-14 17:34:35 +01:00
parent d842acd57e
commit e14d1d7e41
4 changed files with 22 additions and 8 deletions

View File

@ -1278,13 +1278,17 @@ exprfmt(Fmt *f, Node *n, int prec)
static int
nodefmt(Fmt *f, Node *n)
{
Type *t;
if(f->flags&FmtLong && n->type != T) {
if(n->type->etype == TNIL)
t = n->type;
if(n->orig != N)
n = n->orig;
if(f->flags&FmtLong && t != T) {
if(t->etype == TNIL)
return fmtprint(f, "nil");
else
return fmtprint(f, "%N (type %T)", n, n->type);
return fmtprint(f, "%N (type %T)", n, t);
}
// TODO inlining produces expressions with ninits. we can't print these yet.
@ -1479,8 +1483,6 @@ Nconv(Fmt *fp)
switch(fmtmode) {
case FErr:
case FExp:
if(n->orig != N)
n = n->orig;
r = nodefmt(fp, n);
break;
case FDbg:

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@ -15,7 +15,7 @@ var (
_ = sum()
_ = sum(1.0, 2.0)
_ = sum(1.5) // ERROR "integer"
_ = sum("hello") // ERROR ".hello. .type ideal string. as type int|incompatible"
_ = sum("hello") // ERROR ".hello. .type string. as type int|incompatible"
_ = sum([]int{1}) // ERROR "\[\]int literal.*as type int|incompatible"
)

12
test/fixedbugs/bug386.go Normal file
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@ -0,0 +1,12 @@
// errchk $G $D/$F.go
// Copyright 2011 The Go Authors. All rights reserved.
// Use of this source code is governed by a BSD-style
// license that can be found in the LICENSE file.
// Issue 2451, 2452
package foo
func f() error { return 0 } // ERROR "cannot use 0 .type int."
func g() error { return -1 } // ERROR "cannot use -1 .type int."

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@ -37,7 +37,7 @@ func main() {
asBool(true)
asBool(*&b)
asBool(Bool(true))
asBool(1 != 2) // ERROR "cannot use.*type ideal bool.*as type Bool"
asBool(1 != 2) // ERROR "cannot use.*type bool.*as type Bool"
asBool(i < j) // ERROR "cannot use.*type bool.*as type Bool"
_, b = m[2] // ERROR "cannot .* bool.*type Bool"