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math: fix inaccurate result of Exp(1)
The existing implementation is translated from C, which uses a polynomial coefficient very close to 1/6. If the function uses 1/6 as this coeffient, the result of Exp(1) will be more accurate. And this change doesn't introduce more error to Exp function. Fixes #20319 Change-Id: I94c236a18cf95570ebb69f7fb99884b0d7cf5f6e Reviewed-on: https://go-review.googlesource.com/49294 Reviewed-by: Robert Griesemer <gri@golang.org>
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@ -953,6 +953,7 @@ var vfexpSC = []float64{
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// Issue 18912
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1.48852223e+09,
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1.4885222e+09,
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1,
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}
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var expSC = []float64{
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0,
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@ -963,6 +964,7 @@ var expSC = []float64{
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Inf(1),
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Inf(1),
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Inf(1),
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2.718281828459045,
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}
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var vfexp2SC = []float64{
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@ -44,7 +44,7 @@ func Exp(x float64) float64
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// the interval [0,0.34658]:
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// Write
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// R(r**2) = r*(exp(r)+1)/(exp(r)-1) = 2 + r*r/6 - r**4/360 + ...
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// We use a special Remes algorithm on [0,0.34658] to generate
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// We use a special Remez algorithm on [0,0.34658] to generate
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// a polynomial of degree 5 to approximate R. The maximum error
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// of this polynomial approximation is bounded by 2**-59. In
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// other words,
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@ -175,7 +175,7 @@ func exp2(x float64) float64 {
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// exp1 returns e**r × 2**k where r = hi - lo and |r| ≤ ln(2)/2.
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func expmulti(hi, lo float64, k int) float64 {
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const (
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P1 = 1.66666666666666019037e-01 /* 0x3FC55555; 0x5555553E */
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P1 = 1.66666666666666657415e-01 /* 0x3FC55555; 0x55555555 */
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P2 = -2.77777777770155933842e-03 /* 0xBF66C16C; 0x16BEBD93 */
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P3 = 6.61375632143793436117e-05 /* 0x3F11566A; 0xAF25DE2C */
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P4 = -1.65339022054652515390e-06 /* 0xBEBBBD41; 0xC5D26BF1 */
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