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runtime: fix tiny allocator
When a new tiny block is allocated because we're allocating an object that won't fit into the current block, mallocgc saves the new block if it has more space leftover than the old block. However, the logic for this was subtly broken in golang.org/cl/2814, resulting in never saving (or consequently reusing) a tiny block. Change-Id: Ib5f6769451fb82877ddeefe75dfe79ed4a04fd40 Reviewed-on: https://go-review.googlesource.com/16330 Run-TryBot: Matthew Dempsky <mdempsky@google.com> TryBot-Result: Gobot Gobot <gobot@golang.org> Reviewed-by: Ian Lance Taylor <iant@golang.org>
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@ -615,7 +615,7 @@ func mallocgc(size uintptr, typ *_type, flags uint32) unsafe.Pointer {
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(*[2]uint64)(x)[1] = 0
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// See if we need to replace the existing tiny block with the new one
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// based on amount of remaining free space.
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if size < c.tinyoffset {
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if size < c.tinyoffset || c.tiny == nil {
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c.tiny = x
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c.tinyoffset = size
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}
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@ -82,6 +82,23 @@ func TestStringConcatenationAllocs(t *testing.T) {
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}
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}
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func TestTinyAlloc(t *testing.T) {
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const N = 16
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var v [N]unsafe.Pointer
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for i := range v {
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v[i] = unsafe.Pointer(new(byte))
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}
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chunks := make(map[uintptr]bool, N)
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for _, p := range v {
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chunks[uintptr(p)&^7] = true
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}
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if len(chunks) == N {
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t.Fatal("no bytes allocated within the same 8-byte chunk")
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}
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}
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var mallocSink uintptr
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func BenchmarkMalloc8(b *testing.B) {
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