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cmd/compile: schedule in-register OpArg first
OpArgXXXReg values must be scheduled at the very top, as their registers need to be live at the beginning before any other use of the register. Change-Id: Ic76768bb74da402adbe61db3b2d174ecd3f9fffc Reviewed-on: https://go-review.googlesource.com/c/go/+/306329 Trust: Cherry Zhang <cherryyz@google.com> Run-TryBot: Cherry Zhang <cherryyz@google.com> TryBot-Result: Go Bot <gobot@golang.org> Reviewed-by: Than McIntosh <thanm@google.com>
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@ -137,7 +137,14 @@ func schedule(f *Func) {
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case v.Op == OpVarDef:
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case v.Op == OpVarDef:
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// We want all the vardefs next.
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// We want all the vardefs next.
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score[v.ID] = ScoreVarDef
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score[v.ID] = ScoreVarDef
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case v.Op == OpArg || v.Op == OpArgIntReg || v.Op == OpArgFloatReg:
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case v.Op == OpArgIntReg || v.Op == OpArgFloatReg:
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// In-register args must be scheduled as early as possible to ensure that the
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// context register is not stomped. They should only appear in the entry block.
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if b != f.Entry {
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f.Fatalf("%s appeared outside of entry block, b=%s", v.Op, b.String())
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}
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score[v.ID] = ScorePhi
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case v.Op == OpArg:
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// We want all the args as early as possible, for better debugging.
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// We want all the args as early as possible, for better debugging.
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score[v.ID] = ScoreArg
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score[v.ID] = ScoreArg
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case v.Type.IsMemory():
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case v.Type.IsMemory():
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