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compress/bzip2: simplify Huffman tree construction
This change simplifies the construction of the Huffman tree in the bzip2 package by replacing custom sort logic with the more concise and idiomatic use of "slices" and "cmp" packages.
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@ -4,7 +4,10 @@
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package bzip2
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package bzip2
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import "sort"
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import (
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"cmp"
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"slices"
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)
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// A huffmanTree is a binary tree which is navigated, bit-by-bit to reach a
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// A huffmanTree is a binary tree which is navigated, bit-by-bit to reach a
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// symbol.
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// symbol.
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@ -100,17 +103,11 @@ func newHuffmanTree(lengths []uint8) (huffmanTree, error) {
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pairs[i].length = length
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pairs[i].length = length
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}
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}
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sort.Slice(pairs, func(i, j int) bool {
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slices.SortFunc(pairs, func(a, b huffmanSymbolLengthPair) int {
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if pairs[i].length < pairs[j].length {
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if c := cmp.Compare(a.length, b.length); c != 0 {
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return true
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return c
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}
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}
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if pairs[i].length > pairs[j].length {
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return cmp.Compare(a.value, b.value)
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return false
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}
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if pairs[i].value < pairs[j].value {
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return true
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}
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return false
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})
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})
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// Now we assign codes to the symbols, starting with the longest code.
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// Now we assign codes to the symbols, starting with the longest code.
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@ -135,8 +132,8 @@ func newHuffmanTree(lengths []uint8) (huffmanTree, error) {
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// Now we can sort by the code so that the left half of each branch are
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// Now we can sort by the code so that the left half of each branch are
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// grouped together, recursively.
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// grouped together, recursively.
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sort.Slice(codes, func(i, j int) bool {
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slices.SortFunc(codes, func(a, b huffmanCode) int {
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return codes[i].code < codes[j].code
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return cmp.Compare(a.code, b.code)
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})
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})
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t.nodes = make([]huffmanNode, len(codes))
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t.nodes = make([]huffmanNode, len(codes))
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