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runtime: remove indentation in evacuate

Combine conditions into a single if statement.
This is more readable.

It should generate identical machine code, but it doesn't.
The new code is shorter.

Change-Id: I9bf52f8f288b0df97a2b9b4e4183f6ca74175e8a
Reviewed-on: https://go-review.googlesource.com/54651
Run-TryBot: Josh Bleecher Snyder <josharian@gmail.com>
TryBot-Result: Gobot Gobot <gobot@golang.org>
Reviewed-by: Martin Möhrmann <moehrmann@google.com>
This commit is contained in:
Josh Bleecher Snyder 2017-08-10 06:46:36 -07:00
parent 38044eca7c
commit a6136ded32

View File

@ -1088,28 +1088,26 @@ func evacuate(t *maptype, h *hmap, oldbucket uintptr) {
// Compute hash to make our evacuation decision (whether we need
// to send this key/value to bucket x or bucket y).
hash := alg.hash(k2, uintptr(h.hash0))
if h.flags&iterator != 0 {
if !t.reflexivekey && !alg.equal(k2, k2) {
// If key != key (NaNs), then the hash could be (and probably
// will be) entirely different from the old hash. Moreover,
// it isn't reproducible. Reproducibility is required in the
// presence of iterators, as our evacuation decision must
// match whatever decision the iterator made.
// Fortunately, we have the freedom to send these keys either
// way. Also, tophash is meaningless for these kinds of keys.
// We let the low bit of tophash drive the evacuation decision.
// We recompute a new random tophash for the next level so
// these keys will get evenly distributed across all buckets
// after multiple grows.
if top&1 != 0 {
hash |= newbit
} else {
hash &^= newbit
}
top = uint8(hash >> (sys.PtrSize*8 - 8))
if top < minTopHash {
top += minTopHash
}
if h.flags&iterator != 0 && !t.reflexivekey && !alg.equal(k2, k2) {
// If key != key (NaNs), then the hash could be (and probably
// will be) entirely different from the old hash. Moreover,
// it isn't reproducible. Reproducibility is required in the
// presence of iterators, as our evacuation decision must
// match whatever decision the iterator made.
// Fortunately, we have the freedom to send these keys either
// way. Also, tophash is meaningless for these kinds of keys.
// We let the low bit of tophash drive the evacuation decision.
// We recompute a new random tophash for the next level so
// these keys will get evenly distributed across all buckets
// after multiple grows.
if top&1 != 0 {
hash |= newbit
} else {
hash &^= newbit
}
top = uint8(hash >> (sys.PtrSize*8 - 8))
if top < minTopHash {
top += minTopHash
}
}
useX = hash&newbit == 0