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strings: update Join parameter name for clarity
Change-Id: I83f806e76ef4d268b187bd273d78ceb41b7e8fa5
GitHub-Last-Rev: ee82eaae64
GitHub-Pull-Request: golang/go#36194
Reviewed-on: https://go-review.googlesource.com/c/go/+/211799
Reviewed-by: Brad Fitzpatrick <bradfitz@golang.org>
Run-TryBot: Brad Fitzpatrick <bradfitz@golang.org>
TryBot-Result: Gobot Gobot <gobot@golang.org>
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@ -420,24 +420,24 @@ func FieldsFunc(s string, f func(rune) bool) []string {
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return a
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}
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// Join concatenates the elements of a to create a single string. The separator string
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// sep is placed between elements in the resulting string.
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func Join(a []string, sep string) string {
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switch len(a) {
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// Join concatenates the elements of its first argument to create a single string. The separator
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// string sep is placed between elements in the resulting string.
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func Join(elems []string, sep string) string {
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switch len(elems) {
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case 0:
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return ""
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case 1:
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return a[0]
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return elems[0]
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}
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n := len(sep) * (len(a) - 1)
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for i := 0; i < len(a); i++ {
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n += len(a[i])
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n := len(sep) * (len(elems) - 1)
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for i := 0; i < len(elems); i++ {
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n += len(elems[i])
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}
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var b Builder
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b.Grow(n)
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b.WriteString(a[0])
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for _, s := range a[1:] {
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b.WriteString(elems[0])
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for _, s := range elems[1:] {
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b.WriteString(sep)
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b.WriteString(s)
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}
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