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fmtsort: sort interfaces deterministically
Previously, the result of sorting a map[interface{}] containing
multiple concrete types was non-deterministic. To ensure consistent
results, sort first by type name, then by concrete value.
Fixes #30398
Change-Id: I10fd4b6a74eefbc87136853af6b2e689bc76ae9d
GitHub-Last-Rev: 1b07f0c275
GitHub-Pull-Request: golang/go#30406
Reviewed-on: https://go-review.googlesource.com/c/163745
Reviewed-by: Rob Pike <r@golang.org>
Reviewed-by: Keith Randall <khr@golang.org>
Run-TryBot: Keith Randall <khr@golang.org>
TryBot-Result: Gobot Gobot <gobot@golang.org>
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@ -167,7 +167,7 @@ func compare(aVal, bVal reflect.Value) int {
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if c, ok := nilCompare(aVal, bVal); ok {
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return c
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}
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c := compare(reflect.ValueOf(aType), reflect.ValueOf(bType))
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c := compare(reflect.ValueOf(aVal.Elem().Type()), reflect.ValueOf(bVal.Elem().Type()))
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if c != 0 {
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return c
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}
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@ -126,10 +126,6 @@ var sortTests = []sortTest{
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map[[2]int]string{{7, 2}: "72", {7, 1}: "71", {3, 4}: "34"},
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"[3 4]:34 [7 1]:71 [7 2]:72",
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},
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{
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map[interface{}]string{7: "7", 4: "4", 3: "3", nil: "nil"},
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"<nil>:nil 3:3 4:4 7:7",
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},
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}
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func sprint(data interface{}) string {
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@ -210,3 +206,41 @@ func TestOrder(t *testing.T) {
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}
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}
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}
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func TestInterface(t *testing.T) {
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// A map containing multiple concrete types should be sorted by type,
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// then value. However, the relative ordering of types is unspecified,
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// so test this by checking the presence of sorted subgroups.
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m := map[interface{}]string{
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[2]int{1, 0}: "",
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[2]int{0, 1}: "",
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true: "",
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false: "",
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3.1: "",
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2.1: "",
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1.1: "",
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math.NaN(): "",
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3: "",
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2: "",
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1: "",
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"c": "",
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"b": "",
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"a": "",
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struct{ x, y int }{1, 0}: "",
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struct{ x, y int }{0, 1}: "",
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}
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got := sprint(m)
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typeGroups := []string{
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"NaN: 1.1: 2.1: 3.1:", // float64
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"false: true:", // bool
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"1: 2: 3:", // int
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"a: b: c:", // string
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"[0 1]: [1 0]:", // [2]int
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"{0 1}: {1 0}:", // struct{ x int; y int }
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}
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for _, g := range typeGroups {
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if !strings.Contains(got, g) {
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t.Errorf("sorted map should contain %q", g)
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}
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}
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}
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