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time: simplify Duration.String example

The existing example is needlessly complex.
You have to know that t.Sub returns a Duration
and also have to mentally subtract the two times
to understand what duration should be printed.

Rewrite to focus on just the Duration.String operation.

Change-Id: I00765b6019c07a6ff03022625b556c2b9ba87c09
Reviewed-on: https://go-review.googlesource.com/c/go/+/234893
Run-TryBot: Russ Cox <rsc@golang.org>
TryBot-Result: Gobot Gobot <gobot@golang.org>
Reviewed-by: Ian Lance Taylor <iant@golang.org>
Reviewed-by: Brad Fitzpatrick <bradfitz@golang.org>
This commit is contained in:
Russ Cox 2020-05-21 20:53:45 -04:00
parent ea2de3346f
commit 9acdc705e7

View File

@ -50,10 +50,11 @@ func ExampleDuration_Round() {
} }
func ExampleDuration_String() { func ExampleDuration_String() {
t1 := time.Date(2016, time.August, 15, 0, 0, 0, 0, time.UTC) fmt.Println(1*time.Hour + 2*time.Minute + 300*time.Millisecond)
t2 := time.Date(2017, time.February, 16, 0, 0, 0, 0, time.UTC) fmt.Println(300*time.Millisecond)
fmt.Println(t2.Sub(t1).String()) // Output:
// Output: 4440h0m0s // 1h2m0.3s
// 300ms
} }
func ExampleDuration_Truncate() { func ExampleDuration_Truncate() {