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cmd/compile: do not substitute OGOTO inside a closure when inlining
The inlsubst already does the same thing for OLABEL, so we must do the same thing for OGOTO. Otherwise, new inlined OGOTO node will be associated with non-existed label. Fixes #45947 Change-Id: I40eef095f57fd3438c38a0b5d9751d5d7ebf759e Reviewed-on: https://go-review.googlesource.com/c/go/+/316931 Trust: Cuong Manh Le <cuong.manhle.vn@gmail.com> Trust: Dan Scales <danscales@google.com> Run-TryBot: Cuong Manh Le <cuong.manhle.vn@gmail.com> TryBot-Result: Go Bot <gobot@golang.org> Reviewed-by: Dan Scales <danscales@google.com>
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@ -1394,6 +1394,10 @@ func (subst *inlsubst) node(n ir.Node) ir.Node {
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return ir.NewBlockStmt(base.Pos, init)
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case ir.OGOTO:
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if subst.newclofn != nil {
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// Don't do special substitutions if inside a closure
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break
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}
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n := n.(*ir.BranchStmt)
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m := ir.Copy(n).(*ir.BranchStmt)
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m.SetPos(subst.updatedPos(m.Pos()))
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16
test/fixedbugs/issue45947.go
Normal file
16
test/fixedbugs/issue45947.go
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@ -0,0 +1,16 @@
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// compile
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// Copyright 2021 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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package p
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func f() {
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_ = func() func() {
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return func() {
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l:
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goto l
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}
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}()
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}
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