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go/types: don't crash for erroneous program involving a shift in a declaration cycle

R=1.6

Fixes #11347.

Change-Id: Ic6b09f38682500ffcc8d1f96e58f7237a7528806
Reviewed-on: https://go-review.googlesource.com/12812
Reviewed-by: Alan Donovan <adonovan@google.com>
This commit is contained in:
Robert Griesemer 2015-07-28 15:44:19 -07:00
parent f1b5bb9588
commit 80eca3a98b
2 changed files with 24 additions and 7 deletions

View File

@ -681,13 +681,24 @@ func (check *Checker) shift(x, y *operand, op token.Token) {
// constant is what it would be if the shift expression
// were replaced by its left operand alone.".
//
// Delay operand checking until we know the final type:
// The lhs expression must be in the untyped map, mark
// the entry as lhs shift operand.
info, found := check.untyped[x.expr]
assert(found)
info.isLhs = true
check.untyped[x.expr] = info
// Delay operand checking until we know the final type
// by marking the lhs expression as lhs shift operand.
//
// Usually (in correct programs), the lhs expression
// is in the untyped map. However, it is possible to
// create incorrect programs where the same expression
// is evaluated twice (via a declaration cycle) such
// that the lhs expression type is determined in the
// first round and thus deleted from the map, and then
// not found in the second round (double insertion of
// the same expr node still just leads to one entry for
// that node, and it can only be deleted once).
// Be cautious and check for presence of entry.
// Example: var e, f = int(1<<""[f]) // issue 11347
if info, found := check.untyped[x.expr]; found {
info.isLhs = true
check.untyped[x.expr] = info
}
// keep x's type
x.mode = value
return

View File

@ -95,3 +95,9 @@ func issue10979() {
m()
}
}
// issue11347
// These should not crash.
var a1, b1 /* ERROR cycle */ , c1 /* ERROR cycle */ b1 = 0 > 0<<""[""[c1]]>c1
var a2, b2 /* ERROR cycle */ = 0 /* ERROR mismatch */ /* ERROR mismatch */ > 0<<""[b2]
var a3, b3 /* ERROR cycle */ = int /* ERROR mismatch */ /* ERROR mismatch */ (1<<""[b3])