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cmd/compile/internal-abi: fix ABI0-equivalence for zero-sized values
This fixes a bug in the internal ABI specification that made it not equivalent to ABI0 even with zero architectural argument registers in the case of a zero-sized argument with alignment > 1. In ABI0, even zero-sized arguments cause alignment padding in the stack frame. Currently, in the internal ABI, zero-sized arguments get register-assigned even if there are no registers because they don't consume any registers. Hence, they don't create alignment padding in the stack frame. Fix this by stack-assigning zero-sized arguments. For #40724. Change-Id: I1f5a95a94fed8b5313a360e5e76875701ba5f562 Reviewed-on: https://go-review.googlesource.com/c/go/+/295791 Trust: Austin Clements <austin@google.com> Reviewed-by: Cherry Zhang <cherryyz@google.com> Reviewed-by: Than McIntosh <thanm@google.com>
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@ -153,6 +153,7 @@ Assigning a receiver, argument, or result V of underlying type T works
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as follows:
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1. Remember I and FP.
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1. If T has zero size, add T to the stack sequence S and return.
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1. Try to register-assign V.
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1. If step 2 failed, reset I and FP to the values from step 1, add T
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to the stack sequence S, and assign V to this field in S.
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@ -295,6 +296,15 @@ An architecture may still define register meanings that aren’t
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compatible with ABI0, but these differences should be easy to account
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for in the compiler.
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The assignment algorithm assigns zero-sized values to the stack
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(assignment step 2) in order to support ABI0-equivalence.
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While these values take no space themselves, they do result in
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alignment padding on the stack in ABI0.
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Without this step, the internal ABI would register-assign zero-sized
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values even on architectures that provide no argument registers
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because they don't consume any registers, and hence not add alignment
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padding to the stack.
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The algorithm reserves spill space for arguments in the caller’s frame
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so that the compiler can generate a stack growth path that spills into
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this reserved space.
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