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cmd/compile: remove listsort
The listsort function is no longer used, except in a test. Change the test to use sort.Sort instead. Change-Id: Ib634705cc1bc3b1d8fc3795bd4ed2894e6abc284 Reviewed-on: https://go-review.googlesource.com/19964 Reviewed-by: Brad Fitzpatrick <bradfitz@golang.org>
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@ -6,6 +6,7 @@ package gc
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import (
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"reflect"
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"sort"
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"testing"
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)
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@ -134,7 +135,7 @@ func nodelist2slice(nl *NodeList) []*Node {
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return s
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}
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func TestListsort(t *testing.T) {
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func TestStackvarSort(t *testing.T) {
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inp := []*Node{
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{Class: PFUNC, Type: &Type{}, Name: &Name{}, Sym: &Sym{}},
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{Class: PAUTO, Type: &Type{}, Name: &Name{}, Sym: &Sym{}},
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@ -173,13 +174,11 @@ func TestListsort(t *testing.T) {
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haspointers(inp[i].Type)
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}
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nl := slice2nodelist(inp)
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listsort(&nl, cmpstackvarlt)
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got := nodelist2slice(nl)
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if !reflect.DeepEqual(want, got) {
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t.Error("listsort failed")
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for i := range got {
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g := got[i]
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sort.Sort(byStackVar(inp))
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if !reflect.DeepEqual(want, inp) {
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t.Error("sort failed")
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for i := range inp {
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g := inp[i]
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w := want[i]
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eq := reflect.DeepEqual(w, g)
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if !eq {
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@ -411,69 +411,6 @@ func list(l *NodeList, n *Node) *NodeList {
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return concat(l, list1(n))
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}
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// listsort sorts *l in place according to the comparison function lt.
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// The algorithm expects lt(a, b) to be equivalent to a < b.
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// The algorithm is mergesort, so it is guaranteed to be O(n log n).
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func listsort(l **NodeList, lt func(*Node, *Node) bool) {
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if *l == nil || (*l).Next == nil {
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return
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}
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l1 := *l
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l2 := *l
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for {
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l2 = l2.Next
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if l2 == nil {
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break
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}
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l2 = l2.Next
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if l2 == nil {
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break
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}
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l1 = l1.Next
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}
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l2 = l1.Next
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l1.Next = nil
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l2.End = (*l).End
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(*l).End = l1
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l1 = *l
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listsort(&l1, lt)
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listsort(&l2, lt)
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if lt(l1.N, l2.N) {
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*l = l1
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} else {
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*l = l2
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l2 = l1
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l1 = *l
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}
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// now l1 == *l; and l1 < l2
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var le *NodeList
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for (l1 != nil) && (l2 != nil) {
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for (l1.Next != nil) && lt(l1.Next.N, l2.N) {
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l1 = l1.Next
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}
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// l1 is last one from l1 that is < l2
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le = l1.Next // le is the rest of l1, first one that is >= l2
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if le != nil {
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le.End = (*l).End
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}
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(*l).End = l1 // cut *l at l1
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*l = concat(*l, l2) // glue l2 to *l's tail
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l1 = l2 // l1 is the first element of *l that is < the new l2
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l2 = le // ... because l2 now is the old tail of l1
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}
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*l = concat(*l, l2) // any remainder
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}
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// count returns the length of the list l.
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func count(l *NodeList) int {
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n := int64(0)
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