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go/types, types2: clean up defined type identity check/unification
Factor out check for identical origin. Match unification code with type identity check. Add a test case for #53692. Change-Id: I1238b28297a5ac549e99261c8a085dd46f3dd65f Reviewed-on: https://go-review.googlesource.com/c/go/+/474197 Run-TryBot: Robert Griesemer <gri@google.com> Reviewed-by: Robert Findley <rfindley@google.com> Reviewed-by: Robert Griesemer <gri@google.com> TryBot-Result: Gopher Robot <gobot@golang.org> Auto-Submit: Robert Griesemer <gri@google.com>
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@ -433,33 +433,23 @@ func (c *comparer) identical(x, y Type, p *ifacePair) bool {
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case *Named:
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// Two named types are identical if their type names originate
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// in the same type declaration.
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// in the same type declaration; if they are instantiated they
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// must have identical type argument lists.
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if y, ok := y.(*Named); ok {
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// check type arguments before origins to match unifier
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// (for correct source code we need to do all checks so
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// order doesn't matter)
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xargs := x.TypeArgs().list()
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yargs := y.TypeArgs().list()
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if len(xargs) != len(yargs) {
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return false
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}
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if len(xargs) > 0 {
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// Instances are identical if their original type and type arguments
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// are identical.
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if !Identical(x.Origin(), y.Origin()) {
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return false
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}
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for i, xa := range xargs {
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if !Identical(xa, yargs[i]) {
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for i, xarg := range xargs {
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if !Identical(xarg, yargs[i]) {
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return false
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}
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}
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return true
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}
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// TODO(gri) Why is x == y not sufficient? And if it is,
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// we can just return false here because x == y
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// is caught in the very beginning of this function.
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return x.obj == y.obj
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return indenticalOrigin(x, y)
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}
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case *TypeParam:
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@ -475,6 +465,12 @@ func (c *comparer) identical(x, y Type, p *ifacePair) bool {
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return false
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}
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// identicalOrigin reports whether x and y originated in the same declaration.
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func indenticalOrigin(x, y *Named) bool {
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// TODO(gri) is this correct?
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return x.Origin().obj == y.Origin().obj
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}
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// identicalInstance reports if two type instantiations are identical.
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// Instantiations are identical if their origin and type arguments are
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// identical.
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@ -506,26 +506,24 @@ func (u *unifier) nify(x, y Type, p *ifacePair) (result bool) {
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}
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case *Named:
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// TODO(gri) This code differs now from the parallel code in Checker.identical. Investigate.
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// Two named types are identical if their type names originate
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// in the same type declaration; if they are instantiated they
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// must have identical type argument lists.
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if y, ok := y.(*Named); ok {
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// check type arguments before origins so they unify
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// even if the origins don't match; for better error
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// messages (see go.dev/issue/53692)
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xargs := x.TypeArgs().list()
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yargs := y.TypeArgs().list()
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if len(xargs) != len(yargs) {
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return false
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}
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// TODO(gri) This is not always correct: two types may have the same names
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// in the same package if one of them is nested in a function.
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// Extremely unlikely but we need an always correct solution.
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if x.obj.pkg == y.obj.pkg && x.obj.name == y.obj.name {
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for i, x := range xargs {
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if !u.nify(x, yargs[i], p) {
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for i, xarg := range xargs {
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if !u.nify(xarg, yargs[i], p) {
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return false
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}
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}
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return true
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}
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return indenticalOrigin(x, y)
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}
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case *TypeParam:
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@ -435,33 +435,23 @@ func (c *comparer) identical(x, y Type, p *ifacePair) bool {
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case *Named:
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// Two named types are identical if their type names originate
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// in the same type declaration.
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// in the same type declaration; if they are instantiated they
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// must have identical type argument lists.
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if y, ok := y.(*Named); ok {
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// check type arguments before origins to match unifier
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// (for correct source code we need to do all checks so
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// order doesn't matter)
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xargs := x.TypeArgs().list()
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yargs := y.TypeArgs().list()
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if len(xargs) != len(yargs) {
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return false
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}
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if len(xargs) > 0 {
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// Instances are identical if their original type and type arguments
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// are identical.
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if !Identical(x.Origin(), y.Origin()) {
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return false
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}
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for i, xa := range xargs {
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if !Identical(xa, yargs[i]) {
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for i, xarg := range xargs {
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if !Identical(xarg, yargs[i]) {
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return false
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}
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}
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return true
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}
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// TODO(gri) Why is x == y not sufficient? And if it is,
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// we can just return false here because x == y
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// is caught in the very beginning of this function.
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return x.obj == y.obj
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return indenticalOrigin(x, y)
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}
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case *TypeParam:
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@ -477,6 +467,12 @@ func (c *comparer) identical(x, y Type, p *ifacePair) bool {
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return false
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}
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// identicalOrigin reports whether x and y originated in the same declaration.
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func indenticalOrigin(x, y *Named) bool {
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// TODO(gri) is this correct?
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return x.Origin().obj == y.Origin().obj
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}
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// identicalInstance reports if two type instantiations are identical.
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// Instantiations are identical if their origin and type arguments are
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// identical.
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@ -508,26 +508,24 @@ func (u *unifier) nify(x, y Type, p *ifacePair) (result bool) {
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}
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case *Named:
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// TODO(gri) This code differs now from the parallel code in Checker.identical. Investigate.
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// Two named types are identical if their type names originate
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// in the same type declaration; if they are instantiated they
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// must have identical type argument lists.
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if y, ok := y.(*Named); ok {
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// check type arguments before origins so they unify
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// even if the origins don't match; for better error
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// messages (see go.dev/issue/53692)
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xargs := x.TypeArgs().list()
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yargs := y.TypeArgs().list()
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if len(xargs) != len(yargs) {
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return false
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}
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// TODO(gri) This is not always correct: two types may have the same names
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// in the same package if one of them is nested in a function.
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// Extremely unlikely but we need an always correct solution.
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if x.obj.pkg == y.obj.pkg && x.obj.name == y.obj.name {
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for i, x := range xargs {
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if !u.nify(x, yargs[i], p) {
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for i, xarg := range xargs {
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if !u.nify(xarg, yargs[i], p) {
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return false
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}
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}
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return true
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}
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return indenticalOrigin(x, y)
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}
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case *TypeParam:
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15
src/internal/types/testdata/fixedbugs/issue53692.go
vendored
Normal file
15
src/internal/types/testdata/fixedbugs/issue53692.go
vendored
Normal file
@ -0,0 +1,15 @@
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// Copyright 2023 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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package p
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type Cache[K comparable, V any] interface{}
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type LRU[K comparable, V any] struct{}
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func WithLocking2[K comparable, V any](Cache[K, V]) {}
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func _() {
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WithLocking2[string](LRU /* ERROR "type LRU[string, int] of LRU[string, int]{} does not match inferred type Cache[string, int] for Cache[string, V]" */ [string, int]{})
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}
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