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runtime: fix uint64 division on 386
The uint64 divide function calls _mul64x32 to do a 64x32-bit multiply and then compares the result against the 64-bit numerator. If the result is bigger than the numerator, must use the slow path. Unfortunately, the 64x32 produces a 96-bit product, and only the low 64 bits were being used in the comparison. Return all 96 bits, the bottom 64 via the original uint64* pointer, and the top 32 as the function's return value. Fixes 386 build (broken by ARM division tests). R=golang-dev, iant CC=golang-dev https://golang.org/cl/13722044
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@ -29,6 +29,8 @@
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* C runtime for 64-bit divide.
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*/
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// _mul64x32(r *uint64, a uint64, b uint32)
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// sets *r = low 64 bits of 96-bit product a*b; returns high 32 bits.
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TEXT _mul64by32(SB), NOSPLIT, $0
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MOVL r+0(FP), CX
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MOVL a+4(FP), AX
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@ -38,7 +40,9 @@ TEXT _mul64by32(SB), NOSPLIT, $0
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MOVL a+8(FP), AX
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MULL b+12(FP)
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ADDL AX, BX
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ADCL $0, DX
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MOVL BX, 4(CX)
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MOVL DX, AX
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RET
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TEXT _div64by32(SB), NOSPLIT, $0
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@ -147,7 +147,7 @@ _v2f(Vlong x)
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}
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ulong _div64by32(Vlong, ulong, ulong*);
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void _mul64by32(Vlong*, Vlong, ulong);
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int _mul64by32(Vlong*, Vlong, ulong);
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static void
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slowdodiv(Vlong num, Vlong den, Vlong *q, Vlong *r)
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@ -232,8 +232,7 @@ dodiv(Vlong num, Vlong den, Vlong *qp, Vlong *rp)
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if(den.hi != 0){
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q.hi = 0;
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n = num.hi/den.hi;
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_mul64by32(&x, den, n);
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if(x.hi > num.hi || (x.hi == num.hi && x.lo > num.lo))
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if(_mul64by32(&x, den, n) || x.hi > num.hi || (x.hi == num.hi && x.lo > num.lo))
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slowdodiv(num, den, &q, &r);
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else {
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q.lo = n;
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