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time: fallback to slower TestTicker test after one failure
TestTicker is sensitive to overloaded or slow systems, where a 20ms ticker running for 10 ticks has a total run time out of the range [110ms, 290ms]. To counter this flakiness, it tries five times to get a successful result. This is insufficient--an overloaded test machine can introduce more than 100ms of delay across the test. Reduce the five attempts to two, but use a 1s ticker for 8 ticks in the second attempt. Updates #46474. Updates #35692. Change-Id: Ibd5187b00ccceeb981b652f2af9a1c3766357b78 Reviewed-on: https://go-review.googlesource.com/c/go/+/339892 Trust: Damien Neil <dneil@google.com> Run-TryBot: Damien Neil <dneil@google.com> TryBot-Result: Go Bot <gobot@golang.org> Reviewed-by: Ian Lance Taylor <iant@golang.org>
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@ -15,10 +15,11 @@ func TestTicker(t *testing.T) {
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// We want to test that a ticker takes as much time as expected.
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// Since we don't want the test to run for too long, we don't
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// want to use lengthy times. This makes the test inherently flaky.
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// So only report an error if it fails five times in a row.
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// Start with a short time, but try again with a long one if the
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// first test fails.
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count := 10
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delta := 20 * Millisecond
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baseCount := 10
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baseDelta := 20 * Millisecond
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// On Darwin ARM64 the tick frequency seems limited. Issue 35692.
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if (runtime.GOOS == "darwin" || runtime.GOOS == "ios") && runtime.GOARCH == "arm64" {
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@ -27,8 +28,8 @@ func TestTicker(t *testing.T) {
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// Since tick frequency is limited on Darwin ARM64, use even
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// number to give the ticks more time to let the test pass.
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// See CL 220638.
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count = 6
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delta = 100 * Millisecond
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baseCount = 6
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baseDelta = 100 * Millisecond
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}
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var errs []string
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@ -38,7 +39,17 @@ func TestTicker(t *testing.T) {
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}
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}
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for i := 0; i < 5; i++ {
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for _, test := range []struct {
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count int
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delta Duration
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}{{
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count: baseCount,
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delta: baseDelta,
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}, {
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count: 8,
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delta: 1 * Second,
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}} {
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count, delta := test.count, test.delta
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ticker := NewTicker(delta)
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t0 := Now()
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for i := 0; i < count/2; i++ {
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