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effective go: tweak the words about semicolons, parens in control structures,

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and make and new.

R=golang-dev, adg
CC=golang-dev
https://golang.org/cl/4699043
This commit is contained in:
Rob Pike 2011-07-12 23:45:10 +10:00
parent 9f4c288c16
commit 4c63129545
1 changed files with 9 additions and 6 deletions
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15
doc/effective_go.html
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@ -116,7 +116,7 @@ Some formatting details remain. Very briefly,
<dt>Parentheses</dt>
<dd>
Go needs fewer parentheses: control structures (<code>if</code>,
<code>for</code>, <code>switch</code>) do not require parentheses in
<code>for</code>, <code>switch</code>) do not have parentheses in
their syntax.
Also, the operator precedence hierarchy is shorter and clearer, so
<pre>
@ -405,7 +405,7 @@ break continue fallthrough return ++ -- ) }
<p>
the lexer always inserts a semicolon after the token.
This could be summarized as, &ldquo;if the newline comes
after a token that could end a statement, add a semicolon&rdquo;.
after a token that could end a statement, insert a semicolon&rdquo;.
</p>
<p>
@ -461,7 +461,7 @@ initialization statement like that of <code>for</code>;
and there are new control structures including a type switch and a
multiway communications multiplexer, <code>select</code>.
The syntax is also slightly different:
parentheses are not required
there are no parentheses
and the bodies must always be brace-delimited.
</p>
@ -564,7 +564,7 @@ for i := 0; i &lt; 10; i++ {
<p>
If you're looping over an array, slice, string, or map,
or reading from a channel, a <code>range</code> clause can
manage the loop for you.
manage the loop.
</p>
<pre>
var m map[string]int
@ -943,8 +943,11 @@ Go has two allocation primitives, the built-in functions
They do different things and apply to different types, which can be confusing,
but the rules are simple.
Let's talk about <code>new</code> first.
It's a built-in function essentially the same as its namesakes
in other languages: <code>new(T)</code> allocates zeroed storage for a new item of type
It's a built-in function that allocates memory, but unlike its namesakes
in some other languages it does not <em>initialize</em> the memory,
it only <em>zeroes</em> it.
That is,
<code>new(T)</code> allocates zeroed storage for a new item of type
<code>T</code> and returns its address, a value of type <code>*T</code>.
In Go terminology, it returns a pointer to a newly allocated zero value of type
<code>T</code>.