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regexp: delete Iter methods
They are unused and not that useful anyway. R=rsc CC=golang-dev https://golang.org/cl/2225045
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@ -1149,42 +1149,6 @@ func (re *Regexp) allMatches(s string, b []byte, n int, deliver func([]int)) {
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}
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}
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// TODO: AllMatchesIter and AllMatchesStringIter should change to return submatches as well.
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// AllMatchesIter slices the byte slice b into substrings that are successive
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// matches of the Regexp within b. If n > 0, the function returns at most n
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// matches. Text that does not match the expression will be skipped. Empty
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// matches abutting a preceding match are ignored. The function returns a
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// channel that iterates over the matching substrings.
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func (re *Regexp) AllMatchesIter(b []byte, n int) <-chan []byte {
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if n <= 0 {
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n = len(b) + 1
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}
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c := make(chan []byte, 10)
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go func() {
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re.allMatches("", b, n, func(match []int) { c <- b[match[0]:match[1]] })
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close(c)
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}()
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return c
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}
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// AllMatchesStringIter slices the string s into substrings that are successive
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// matches of the Regexp within s. If n > 0, the function returns at most n
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// matches. Text that does not match the expression will be skipped. Empty
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// matches abutting a preceding match are ignored. The function returns a
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// channel that iterates over the matching substrings.
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func (re *Regexp) AllMatchesStringIter(s string, n int) <-chan string {
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if n <= 0 {
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n = len(s) + 1
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}
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c := make(chan string, 10)
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go func() {
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re.allMatches(s, nil, n, func(match []int) { c <- s[match[0]:match[1]] })
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close(c)
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}()
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return c
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}
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// Find returns a slice holding the text of the leftmost match in b of the regular expression.
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// A return value of nil indicates no match.
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func (re *Regexp) Find(b []byte) []byte {
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