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strings,bytes,regexp: use lists in Split* docstrings
This looks better than the default of using a code block. While at it, fix punctuation. Change-Id: I86abca4da1e9999b7e9043e615ad0988d35a5a46 Reviewed-on: https://go-review.googlesource.com/c/go/+/597656 Reviewed-by: Cherry Mui <cherryyz@google.com> Reviewed-by: Ian Lance Taylor <iant@google.com> Auto-Submit: Ian Lance Taylor <iant@google.com> LUCI-TryBot-Result: Go LUCI <golang-scoped@luci-project-accounts.iam.gserviceaccount.com>
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@ -355,10 +355,9 @@ func genSplit(s, sep []byte, sepSave, n int) [][]byte {
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// the subslices between those separators.
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// If sep is empty, SplitN splits after each UTF-8 sequence.
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// The count determines the number of subslices to return:
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//
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// n > 0: at most n subslices; the last subslice will be the unsplit remainder.
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// n == 0: the result is nil (zero subslices)
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// n < 0: all subslices
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// - n > 0: at most n subslices; the last subslice will be the unsplit remainder;
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// - n == 0: the result is nil (zero subslices);
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// - n < 0: all subslices.
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//
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// To split around the first instance of a separator, see Cut.
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func SplitN(s, sep []byte, n int) [][]byte { return genSplit(s, sep, 0, n) }
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@ -367,10 +366,9 @@ func SplitN(s, sep []byte, n int) [][]byte { return genSplit(s, sep, 0, n) }
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// returns a slice of those subslices.
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// If sep is empty, SplitAfterN splits after each UTF-8 sequence.
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// The count determines the number of subslices to return:
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//
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// n > 0: at most n subslices; the last subslice will be the unsplit remainder.
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// n == 0: the result is nil (zero subslices)
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// n < 0: all subslices
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// - n > 0: at most n subslices; the last subslice will be the unsplit remainder;
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// - n == 0: the result is nil (zero subslices);
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// - n < 0: all subslices.
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func SplitAfterN(s, sep []byte, n int) [][]byte {
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return genSplit(s, sep, len(sep), n)
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}
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@ -1244,10 +1244,9 @@ func (re *Regexp) FindAllStringSubmatchIndex(s string, n int) [][]int {
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// // s: ["", "b", "b", "c", "cadaaae"]
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//
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// The count determines the number of substrings to return:
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//
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// n > 0: at most n substrings; the last substring will be the unsplit remainder.
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// n == 0: the result is nil (zero substrings)
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// n < 0: all substrings
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// - n > 0: at most n substrings; the last substring will be the unsplit remainder;
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// - n == 0: the result is nil (zero substrings);
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// - n < 0: all substrings.
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func (re *Regexp) Split(s string, n int) []string {
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if n == 0 {
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@ -267,10 +267,9 @@ func genSplit(s, sep string, sepSave, n int) []string {
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// the substrings between those separators.
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//
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// The count determines the number of substrings to return:
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//
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// n > 0: at most n substrings; the last substring will be the unsplit remainder.
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// n == 0: the result is nil (zero substrings)
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// n < 0: all substrings
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// - n > 0: at most n substrings; the last substring will be the unsplit remainder;
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// - n == 0: the result is nil (zero substrings);
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// - n < 0: all substrings.
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//
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// Edge cases for s and sep (for example, empty strings) are handled
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// as described in the documentation for [Split].
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@ -282,10 +281,9 @@ func SplitN(s, sep string, n int) []string { return genSplit(s, sep, 0, n) }
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// returns a slice of those substrings.
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//
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// The count determines the number of substrings to return:
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//
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// n > 0: at most n substrings; the last substring will be the unsplit remainder.
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// n == 0: the result is nil (zero substrings)
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// n < 0: all substrings
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// - n > 0: at most n substrings; the last substring will be the unsplit remainder;
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// - n == 0: the result is nil (zero substrings);
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// - n < 0: all substrings.
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//
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// Edge cases for s and sep (for example, empty strings) are handled
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// as described in the documentation for SplitAfter.
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