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runtime: don't try to free OS-created signal stacks
Android's libc creates a signal stack for every thread it creates. In Go, minitSignalStack picks up this existing signal stack and puts it in m.gsignal.stack. However, if we later try to exit a thread (because a locked goroutine is exiting), we'll attempt to stackfree this libc-allocated signal stack and panic. Fix this by clearing gsignal.stack when we unminitSignals in such a situation. This should fix the Android build, which is currently broken. Change-Id: Ieea8d72ef063d22741c54c9daddd8bb84926a488 Reviewed-on: https://go-review.googlesource.com/70130 Reviewed-by: David Crawshaw <crawshaw@golang.org> Reviewed-by: Ian Lance Taylor <iant@golang.org> Run-TryBot: David Crawshaw <crawshaw@golang.org> TryBot-Result: Gobot Gobot <gobot@golang.org>
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@ -1268,7 +1268,13 @@ func mexit(osStack bool) {
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unminit()
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// Free the gsignal stack.
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if m.gsignal != nil {
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//
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// If the signal stack was created outside Go, then gsignal
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// will be non-nil, but unminitSignals set stack.lo to 0
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// (e.g., Android's libc creates all threads with a signal
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// stack, so it's possible for Go to exit them but not control
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// the signal stack).
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if m.gsignal != nil && m.gsignal.stack.lo != 0 {
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stackfree(m.gsignal.stack)
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}
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@ -744,6 +744,10 @@ func unminitSignals() {
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if getg().m.newSigstack {
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st := stackt{ss_flags: _SS_DISABLE}
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sigaltstack(&st, nil)
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} else {
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// We got the signal stack from someone else. Clear it
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// so we don't get confused.
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getg().m.gsignal.stack = stack{}
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}
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}
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