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syscall: match linux Setsid function signature to darwin
SETSID does return an errno - any reason why it has been done this way in zsyscall_linux_* ? Otherwise it should be the same as darwin. From SETSID(2) on my Linux box: ERRORS On error, -1 is returned, and errno is set. Fixes #730 R=rsc CC=golang-dev https://golang.org/cl/878047
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@ -591,7 +591,7 @@ func PtraceDetach(pid int) (errno int) { return ptrace(PTRACE_DETACH, pid, 0, 0)
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//sys Sethostname(p []byte) (errno int)
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//sys Setpgid(pid int, pgid int) (errno int)
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//sys Setrlimit(resource int, rlim *Rlimit) (errno int)
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//sys Setsid() (pid int)
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//sys Setsid() (pid int, errno int)
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//sys Settimeofday(tv *Timeval) (errno int)
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//sys Setuid(uid int) (errno int)
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//sys Splice(rfd int, roff *int64, wfd int, woff *int64, len int, flags int) (n int64, errno int)
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@ -434,9 +434,10 @@ func Setrlimit(resource int, rlim *Rlimit) (errno int) {
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return
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}
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func Setsid() (pid int) {
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r0, _, _ := Syscall(SYS_SETSID, 0, 0, 0)
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func Setsid() (pid int, errno int) {
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r0, _, e1 := Syscall(SYS_SETSID, 0, 0, 0)
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pid = int(r0)
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errno = int(e1)
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return
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}
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@ -434,9 +434,10 @@ func Setrlimit(resource int, rlim *Rlimit) (errno int) {
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return
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}
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func Setsid() (pid int) {
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r0, _, _ := Syscall(SYS_SETSID, 0, 0, 0)
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func Setsid() (pid int, errno int) {
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r0, _, e1 := Syscall(SYS_SETSID, 0, 0, 0)
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pid = int(r0)
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errno = int(e1)
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return
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}
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@ -434,9 +434,10 @@ func Setrlimit(resource int, rlim *Rlimit) (errno int) {
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return
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}
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func Setsid() (pid int) {
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r0, _, _ := Syscall(SYS_SETSID, 0, 0, 0)
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func Setsid() (pid int, errno int) {
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r0, _, e1 := Syscall(SYS_SETSID, 0, 0, 0)
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pid = int(r0)
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errno = int(e1)
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return
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}
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