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runtime: add iterator abstraction for mTreap
This change adds the treapIter type which provides an iterator abstraction for walking over an mTreap. In particular, the mTreap type now has iter() and rev() for iterating both forwards (smallest to largest) and backwards (largest to smallest). It also has an erase() method for erasing elements at the iterator's current position. For #28479. While the expectation is that this change will slow down Go programs, the impact on Go1 and Garbage is negligible. Go1: https://perf.golang.org/search?q=upload:20181214.6 Garbage: https://perf.golang.org/search?q=upload:20181214.11 Change-Id: I60dbebbbe73cbbe7b78d45d2093cec12cc0bc649 Reviewed-on: https://go-review.googlesource.com/c/151537 Run-TryBot: Michael Knyszek <mknyszek@google.com> TryBot-Result: Gobot Gobot <gobot@golang.org> Reviewed-by: Austin Clements <austin@google.com> Reviewed-by: Rick Hudson <rlh@golang.org>
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@ -337,9 +337,9 @@ func ReadMemStatsSlow() (base, slow MemStats) {
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slow.BySize[i].Frees = bySize[i].Frees
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}
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mheap_.scav.treap.walkTreap(func(tn *treapNode) {
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slow.HeapReleased += uint64(tn.spanKey.released())
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})
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for i := mheap_.scav.iter(); i.valid(); i = i.next() {
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slow.HeapReleased += uint64(i.span().released())
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}
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getg().m.mallocing--
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})
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@ -153,6 +153,70 @@ func checkTreapNode(t *treapNode) {
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}
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}
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// treapIter is a unidirectional iterator type which may be used to iterate over a
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// an mTreap in-order forwards (increasing order) or backwards (decreasing order).
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// Its purpose is to hide details about the treap from users when trying to iterate
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// over it.
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//
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// To create iterators over the treap, call iter or rev on an mTreap.
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type treapIter struct {
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t *treapNode
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inc bool // if true, iterate in increasing order, otherwise decreasing order.
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}
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// span returns the span at the current position in the treap.
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// If the treap is not valid, span will panic.
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func (i *treapIter) span() *mspan {
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return i.t.spanKey
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}
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// valid returns whether the iterator represents a valid position
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// in the mTreap.
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func (i *treapIter) valid() bool {
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return i.t != nil
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}
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// next moves the iterator forward by one. Once the iterator
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// ceases to be valid, calling next will panic.
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func (i treapIter) next() treapIter {
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if i.inc {
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i.t = i.t.succ()
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} else {
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i.t = i.t.pred()
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}
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return i
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}
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// iter returns an iterator which may be used to iterate over the treap
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// in increasing order of span size ("forwards").
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func (root *mTreap) iter() treapIter {
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i := treapIter{inc: true}
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t := root.treap
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if t == nil {
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return i
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}
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for t.left != nil {
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t = t.left
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}
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i.t = t
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return i
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}
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// rev returns an iterator which may be used to iterate over the treap
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// in decreasing order of span size ("reverse").
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func (root *mTreap) rev() treapIter {
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i := treapIter{inc: false}
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t := root.treap
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if t == nil {
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return i
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}
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for t.right != nil {
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t = t.right
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}
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i.t = t
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return i
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}
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// insert adds span to the large span treap.
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func (root *mTreap) insert(span *mspan) {
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npages := span.npages
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@ -280,6 +344,16 @@ func (root *mTreap) removeSpan(span *mspan) {
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root.removeNode(t)
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}
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// erase removes the element referred to by the current position of the
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// iterator and returns i.next(). This operation consumes the given
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// iterator, so it should no longer be used and iteration should continue
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// from the returned iterator.
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func (root *mTreap) erase(i treapIter) treapIter {
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n := i.next()
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root.removeNode(i.t)
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return n
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}
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// rotateLeft rotates the tree rooted at node x.
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// turning (x a (y b c)) into (y (x a b) c).
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func (root *mTreap) rotateLeft(x *treapNode) {
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@ -1273,21 +1273,11 @@ func (h *mheap) freeSpanLocked(s *mspan, acctinuse, acctidle bool, unusedsince i
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// starting from the largest span and working down. It then takes those spans
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// and places them in scav. h must be locked.
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func (h *mheap) scavengeLargest(nbytes uintptr) {
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// Find the largest child.
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t := h.free.treap
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if t == nil {
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return
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}
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for t.right != nil {
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t = t.right
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}
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// Iterate over the treap from the largest child to the smallest by
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// starting from the largest and finding its predecessor until we've
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// recovered nbytes worth of physical memory, or it no longer has a
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// predecessor (meaning the treap is now empty).
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// Iterate over the treap backwards (from largest to smallest) scavenging spans
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// until we've reached our quota of nbytes.
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released := uintptr(0)
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for t != nil && released < nbytes {
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s := t.spanKey
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for t := h.free.rev(); released < nbytes && t.valid(); {
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s := t.span()
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r := s.scavenge()
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if r == 0 {
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// Since we're going in order of largest-to-smallest span, this
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@ -1301,9 +1291,7 @@ func (h *mheap) scavengeLargest(nbytes uintptr) {
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// those which have it unset are only in the `free` treap.
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return
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}
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prev := t.pred()
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h.free.removeNode(t)
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t = prev
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t = h.free.erase(t)
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h.scav.insert(s)
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released += r
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}
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@ -1313,34 +1301,20 @@ func (h *mheap) scavengeLargest(nbytes uintptr) {
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// treapNode's span. It then removes the scavenged span from
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// unscav and adds it into scav before continuing. h must be locked.
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func (h *mheap) scavengeAll(now, limit uint64) uintptr {
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// Compute the left-most child in unscav to start iteration from.
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t := h.free.treap
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if t == nil {
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return 0
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}
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for t.left != nil {
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t = t.left
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}
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// Iterate over the treap be computing t's successor before
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// potentially scavenging it.
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// Iterate over the treap scavenging spans if unused for at least limit time.
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released := uintptr(0)
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for t != nil {
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s := t.spanKey
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next := t.succ()
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for t := h.free.iter(); t.valid(); {
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s := t.span()
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if (now - uint64(s.unusedsince)) > limit {
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r := s.scavenge()
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if r != 0 {
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// If we ended up scavenging s, then remove it from unscav
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// and add it to scav. This is safe to do since we've already
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// moved to t's successor.
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h.free.removeNode(t)
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t = h.free.erase(t)
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h.scav.insert(s)
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released += r
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continue
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}
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}
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// Move t forward to its successor to iterate over the whole
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// treap.
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t = next
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t = t.next()
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}
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return released
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}
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