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runtime: handle timer overflow in tsleep
Make sure we never pass a timer into timerproc with a negative duration since it will cause other timers to never expire. Fixes #5321. R=golang-dev, minux.ma, remyoudompheng, mikioh.mikioh, r, bradfitz, rsc, dvyukov CC=golang-dev https://golang.org/cl/9035047
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@ -13,8 +13,13 @@ package time
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#include "malloc.h"
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#include "race.h"
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enum {
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debug = 0,
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};
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static Timers timers;
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static void addtimer(Timer*);
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static void dumptimers(int8*);
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// Package time APIs.
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// Godoc uses the comments in package time, not these.
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@ -92,6 +97,11 @@ addtimer(Timer *t)
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int32 n;
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Timer **nt;
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// when must never be negative; otherwise timerproc will overflow
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// during its delta calculation and never expire other timers.
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if(t->when < 0)
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t->when = (1LL<<63)-1;
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if(timers.len >= timers.cap) {
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// Grow slice.
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n = 16;
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@ -121,6 +131,8 @@ addtimer(Timer *t)
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timers.timerproc = runtime·newproc1(&timerprocv, nil, 0, 0, addtimer);
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timers.timerproc->issystem = true;
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}
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if(debug)
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dumptimers("addtimer");
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}
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// Delete timer t from the heap.
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@ -157,6 +169,8 @@ runtime·deltimer(Timer *t)
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siftup(i);
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siftdown(i);
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}
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if(debug)
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dumptimers("deltimer");
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runtime·unlock(&timers);
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return true;
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}
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@ -285,3 +299,18 @@ siftdown(int32 i)
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i = c;
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}
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}
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static void
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dumptimers(int8 *msg)
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{
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Timer *t;
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int32 i;
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runtime·printf("timers: %s\n", msg);
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for(i = 0; i < timers.len; i++) {
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t = timers.t[i];
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runtime·printf("\t%d\t%p:\ti %d when %D period %D fn %p\n",
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i, t, t->i, t->when, t->period, t->fv->fn);
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}
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runtime·printf("\n");
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}
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@ -4,6 +4,11 @@
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package time
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import (
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"errors"
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"runtime"
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)
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func init() {
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// force US/Pacific for time zone tests
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ForceUSPacificForTesting()
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@ -11,3 +16,61 @@ func init() {
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var Interrupt = interrupt
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var DaysIn = daysIn
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func empty(now int64, arg interface{}) {}
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// Test that a runtimeTimer with a duration so large it overflows
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// does not cause other timers to hang.
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//
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// This test has to be in internal_test.go since it fiddles with
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// unexported data structures.
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func CheckRuntimeTimerOverflow() error {
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// We manually create a runtimeTimer to bypass the overflow
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// detection logic in NewTimer: we're testing the underlying
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// runtime.addtimer function.
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r := &runtimeTimer{
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when: nano() + (1<<63 - 1),
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f: empty,
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arg: nil,
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}
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startTimer(r)
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const timeout = 100 * Millisecond
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// Start a goroutine that should send on t.C before the timeout.
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t := NewTimer(1)
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defer func() {
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// Subsequent tests won't work correctly if we don't stop the
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// overflow timer and kick the timer proc back into service.
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//
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// The timer proc is now sleeping and can only be awoken by
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// adding a timer to the *beginning* of the heap. We can't
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// wake it up by calling NewTimer since other tests may have
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// left timers running that should have expired before ours.
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// Instead we zero the overflow timer duration and start it
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// once more.
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stopTimer(r)
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t.Stop()
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r.when = 0
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startTimer(r)
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}()
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// Try to receive from t.C before the timeout. It will succeed
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// iff the previous sleep was able to finish. We're forced to
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// spin and yield after trying to receive since we can't start
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// any more timers (they might hang due to the same bug we're
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// now testing).
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stop := Now().Add(timeout)
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for {
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select {
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case <-t.C:
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return nil // It worked!
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default:
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if Now().After(stop) {
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return errors.New("runtime timer stuck: overflow in addtimer")
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}
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runtime.Gosched()
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}
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}
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}
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@ -396,3 +396,9 @@ func TestIssue5745(t *testing.T) {
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timer.Stop()
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t.Error("Should be unreachable.")
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}
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func TestOverflowRuntimeTimer(t *testing.T) {
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if err := CheckRuntimeTimerOverflow(); err != nil {
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t.Fatalf(err.Error())
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}
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}
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