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go/parser: remove unused method checkBinaryExpr
Change-Id: Ica981657e50e30cbfa1757e8457819a479f11c7d Reviewed-on: https://go-review.googlesource.com/c/go/+/412775 Reviewed-by: Ian Lance Taylor <iant@google.com> TryBot-Result: Gopher Robot <gobot@golang.org> Auto-Submit: Robert Griesemer <gri@google.com> Run-TryBot: Robert Griesemer <gri@google.com> Reviewed-by: Robert Griesemer <gri@google.com>
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@ -1821,23 +1821,6 @@ func (p *parser) parseBinaryExpr(x ast.Expr, prec1 int, check bool) ast.Expr {
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}
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}
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}
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}
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// checkBinaryExpr checks binary expressions that were not already checked by
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// parseBinaryExpr, because the latter was called with check=false.
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func (p *parser) checkBinaryExpr(x ast.Expr) {
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bx, ok := x.(*ast.BinaryExpr)
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if !ok {
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return
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}
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bx.X = p.checkExpr(bx.X)
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bx.Y = p.checkExpr(bx.Y)
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// parseBinaryExpr checks x and y for each binary expr in a tree, so we
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// traverse the tree of binary exprs starting from x.
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p.checkBinaryExpr(bx.X)
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p.checkBinaryExpr(bx.Y)
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}
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// The result may be a type or even a raw type ([...]int). Callers must
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// The result may be a type or even a raw type ([...]int). Callers must
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// check the result (using checkExpr or checkExprOrType), depending on
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// check the result (using checkExpr or checkExprOrType), depending on
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// context.
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// context.
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