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go_mem: clarified unbuffered channel sync example

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R=rsc
CC=golang-dev
https://golang.org/cl/218063
This commit is contained in:
Andrew Gerrand 2010-02-22 16:51:28 -08:00
parent b0fba898ef
commit 2551cf9d1a
1 changed files with 3 additions and 2 deletions
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@ -190,7 +190,8 @@ the send on that channel completes.
</p> </p>
<p> <p>
This program: This program (as above, but with the send and receive statements swapped and
using an unbuffered channel):
</p> </p>
<pre> <pre>
@ -222,7 +223,7 @@ before the <code>print</code>.
If the channel were buffered (e.g., <code>c = make(chan int, 1)</code>) If the channel were buffered (e.g., <code>c = make(chan int, 1)</code>)
then the program would not be guaranteed to print then the program would not be guaranteed to print
<code>"hello, world"</code>. (It might print the empty string; <code>"hello, world"</code>. (It might print the empty string;
it cannot print <code>"hello, sailor"</code>, nor can it crash.) it cannot print <code>"goodbye, universe"</code>, nor can it crash.)
</p> </p>
<h3>Locks</h3> <h3>Locks</h3>