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regexp: add SubexpNames

Fixes #2440.

R=r, dsymonds
CC=golang-dev
https://golang.org/cl/5559043
This commit is contained in:
Russ Cox 2012-01-19 01:24:01 -05:00
parent e3e93b0f43
commit 21d3721eb8
3 changed files with 67 additions and 23 deletions

View File

@ -289,30 +289,45 @@ func TestLiteralPrefix(t *testing.T) {
}
}
type numSubexpCase struct {
type subexpCase struct {
input string
expected int
num int
names []string
}
var numSubexpCases = []numSubexpCase{
{``, 0},
{`.*`, 0},
{`abba`, 0},
{`ab(b)a`, 1},
{`ab(.*)a`, 1},
{`(.*)ab(.*)a`, 2},
{`(.*)(ab)(.*)a`, 3},
{`(.*)((a)b)(.*)a`, 4},
{`(.*)(\(ab)(.*)a`, 3},
{`(.*)(\(a\)b)(.*)a`, 3},
var subexpCases = []subexpCase{
{``, 0, nil},
{`.*`, 0, nil},
{`abba`, 0, nil},
{`ab(b)a`, 1, []string{"", ""}},
{`ab(.*)a`, 1, []string{"", ""}},
{`(.*)ab(.*)a`, 2, []string{"", "", ""}},
{`(.*)(ab)(.*)a`, 3, []string{"", "", "", ""}},
{`(.*)((a)b)(.*)a`, 4, []string{"", "", "", "", ""}},
{`(.*)(\(ab)(.*)a`, 3, []string{"", "", "", ""}},
{`(.*)(\(a\)b)(.*)a`, 3, []string{"", "", "", ""}},
{`(?P<foo>.*)(?P<bar>(a)b)(?P<foo>.*)a`, 4, []string{"", "foo", "bar", "", "foo"}},
}
func TestNumSubexp(t *testing.T) {
for _, c := range numSubexpCases {
func TestSubexp(t *testing.T) {
for _, c := range subexpCases {
re := MustCompile(c.input)
n := re.NumSubexp()
if n != c.expected {
t.Errorf("NumSubexp for %q returned %d, expected %d", c.input, n, c.expected)
if n != c.num {
t.Errorf("%q: NumSubexp = %d, want %d", c.input, n, c.num)
continue
}
names := re.SubexpNames()
if len(names) != 1+n {
t.Errorf("%q: len(SubexpNames) = %d, want %d", c.input, len(names), n)
continue
}
if c.names != nil {
for i := 0; i < 1+n; i++ {
if names[i] != c.names[i] {
t.Errorf("%q: SubexpNames[%d] = %q, want %q", c.input, i, names[i], c.names[i])
}
}
}
}
}

View File

@ -85,6 +85,7 @@ type Regexp struct {
prefixRune rune // first rune in prefix
cond syntax.EmptyOp // empty-width conditions required at start of match
numSubexp int
subexpNames []string
longest bool
// cache of machines for running regexp
@ -140,6 +141,8 @@ func compile(expr string, mode syntax.Flags, longest bool) (*Regexp, error) {
return nil, err
}
maxCap := re.MaxCap()
capNames := re.CapNames()
re = re.Simplify()
prog, err := syntax.Compile(re)
if err != nil {
@ -149,6 +152,7 @@ func compile(expr string, mode syntax.Flags, longest bool) (*Regexp, error) {
expr: expr,
prog: prog,
numSubexp: maxCap,
subexpNames: capNames,
cond: prog.StartCond(),
longest: longest,
}
@ -223,6 +227,15 @@ func (re *Regexp) NumSubexp() int {
return re.numSubexp
}
// SubexpNames returns the names of the parenthesized subexpressions
// in this Regexp. The name for the first sub-expression is names[1],
// so that if m is a match slice, the name for m[i] is SubexpNames()[i].
// Since the Regexp as a whole cannot be named, names[0] is always
// the empty string. The slice should not be modified.
func (re *Regexp) SubexpNames() []string {
return re.subexpNames
}
const endOfText rune = -1
// input abstracts different representations of the input text. It provides

View File

@ -303,3 +303,19 @@ func (re *Regexp) MaxCap() int {
}
return m
}
// CapNames walks the regexp to find the names of capturing groups.
func (re *Regexp) CapNames() []string {
names := make([]string, re.MaxCap()+1)
re.capNames(names)
return names
}
func (re *Regexp) capNames(names []string) {
if re.Op == OpCapture {
names[re.Cap] = re.Name
}
for _, sub := range re.Sub {
sub.capNames(names)
}
}