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sync/atomic: correct result names for Or methods
A few of the new Or methods of the atomic types use "new" as the name for the result value, but it actually returns the old value. Fix this by renaming the result values to "old". Updates #61395. Change-Id: Ib08db9964f5dfe91929f216d50ff0c9cc891ee49 Reviewed-on: https://go-review.googlesource.com/c/go/+/593855 Reviewed-by: Keith Randall <khr@google.com> Reviewed-by: Keith Randall <khr@golang.org> LUCI-TryBot-Result: Go LUCI <golang-scoped@luci-project-accounts.iam.gserviceaccount.com> Auto-Submit: Austin Clements <austin@google.com> Reviewed-by: Mauri de Souza Meneguzzo <mauri870@gmail.com>
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@ -156,7 +156,7 @@ func (x *Uint32) And(mask uint32) (old uint32) { return AndUint32(&x.v, mask) }
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// Or atomically performs a bitwise OR operation on x using the bitmask
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// provided as mask and returns the old value.
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func (x *Uint32) Or(mask uint32) (new uint32) { return OrUint32(&x.v, mask) }
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func (x *Uint32) Or(mask uint32) (old uint32) { return OrUint32(&x.v, mask) }
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// A Uint64 is an atomic uint64. The zero value is zero.
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type Uint64 struct {
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@ -188,7 +188,7 @@ func (x *Uint64) And(mask uint64) (old uint64) { return AndUint64(&x.v, mask) }
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// Or atomically performs a bitwise OR operation on x using the bitmask
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// provided as mask and returns the old value.
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func (x *Uint64) Or(mask uint64) (new uint64) { return OrUint64(&x.v, mask) }
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func (x *Uint64) Or(mask uint64) (old uint64) { return OrUint64(&x.v, mask) }
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// A Uintptr is an atomic uintptr. The zero value is zero.
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type Uintptr struct {
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