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cmd/compile: don't convert to interface{} for un-comparable types in generic switch
Fixes #53635 Change-Id: I41f383be8870432fc0d29fa83687911ddd8217f1 Reviewed-on: https://go-review.googlesource.com/c/go/+/415634 TryBot-Result: Gopher Robot <gobot@golang.org> Run-TryBot: Cuong Manh Le <cuong.manhle.vn@gmail.com> Reviewed-by: Keith Randall <khr@google.com> Reviewed-by: Keith Randall <khr@golang.org> Reviewed-by: Matthew Dempsky <mdempsky@google.com>
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@ -1214,6 +1214,9 @@ func (subst *subster) node(n ir.Node) ir.Node {
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if m.Tag != nil && m.Tag.Op() == ir.OTYPESW {
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break // Nothing to do here for type switches.
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}
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if m.Tag != nil && !types.IsComparable(m.Tag.Type()) {
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break // Nothing to do here for un-comparable types.
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}
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if m.Tag != nil && !m.Tag.Type().IsEmptyInterface() && m.Tag.Type().HasShape() {
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// To implement a switch on a value that is or has a type parameter, we first convert
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// that thing we're switching on to an interface{}.
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31
test/fixedbugs/issue53635.go
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31
test/fixedbugs/issue53635.go
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@ -0,0 +1,31 @@
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// run
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// Copyright 2022 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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package main
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func main() {
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f[int]()
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}
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func f[T any]() {
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switch []T(nil) {
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case nil:
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default:
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panic("FAIL")
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}
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switch (func() T)(nil) {
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case nil:
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default:
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panic("FAIL")
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}
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switch (map[int]T)(nil) {
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case nil:
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default:
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panic("FAIL")
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}
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}
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