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cmd/go: fix unbuffered channel passed to signal.Notify
Unbuffered channels passed into signal.Notify can be lost as the docs for signal.Notify caution with: Package signal will not block sending to c: the caller must ensure that c has sufficient buffer space to keep up with the expected signal rate. For a channel used for notification of just one signal value, a buffer of size 1 is sufficient. Found by a static analyzer from Orijtech, Inc. called "sigchanyzer", but it'll be donated to the Go project soon. Updates #9399. Change-Id: Ia0690e447582da028694ed65ace7b97961997b84 Reviewed-on: https://go-review.googlesource.com/c/go/+/274332 Trust: Cuong Manh Le <cuong.manhle.vn@gmail.com> Trust: Emmanuel Odeke <emmanuel@orijtech.com> Run-TryBot: Cuong Manh Le <cuong.manhle.vn@gmail.com> Reviewed-by: Bryan C. Mills <bcmills@google.com> Reviewed-by: Emmanuel Odeke <emmanuel@orijtech.com> TryBot-Result: Go Bot <gobot@golang.org>
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@ -15,7 +15,7 @@ var Interrupted = make(chan struct{})
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// processSignals setups signal handler.
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func processSignals() {
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sig := make(chan os.Signal)
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sig := make(chan os.Signal, 1)
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signal.Notify(sig, signalsToIgnore...)
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go func() {
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<-sig
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