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cmd/compile: fix "expression has untyped type" ICE in generic code
During walk, we sometimes desugar OEQ nodes into multiple "untyped bool" expressions, and then use typecheck.Conv to convert back to the original OEQ node's type. However, typecheck.Conv had a short-circuit path that if the type is already identical to the target type according to types.Identical, then we skipped the conversion. This short-circuit is normally fine; but with generic code and shape types, it considers "untyped bool" and "go.shape.bool" to be identical types. And we could end up leaving an expression of "untyped bool", which then fails an internal consistency check later. The simple fix is to change Conv to use types.IdenticalStrict, so that we ensure "untyped bool" gets converted to "go.shape.bool". And for good measure, make the same change to ConvNop. This issue was discovered and reported against unified IR, but the issue was latent within the non-unified frontend too. Fixes #54537. Change-Id: I7559a346b063349b35749e8a2da704be18e51654 Reviewed-on: https://go-review.googlesource.com/c/go/+/424937 TryBot-Result: Gopher Robot <gobot@golang.org> Run-TryBot: Matthew Dempsky <mdempsky@google.com> Reviewed-by: Cuong Manh Le <cuong.manhle.vn@gmail.com> Reviewed-by: David Chase <drchase@google.com>
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@ -1818,7 +1818,7 @@ func isTermNode(n ir.Node) bool {
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}
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func Conv(n ir.Node, t *types.Type) ir.Node {
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if types.Identical(n.Type(), t) {
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if types.IdenticalStrict(n.Type(), t) {
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return n
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}
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n = ir.NewConvExpr(base.Pos, ir.OCONV, nil, n)
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@ -1830,7 +1830,7 @@ func Conv(n ir.Node, t *types.Type) ir.Node {
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// ConvNop converts node n to type t using the OCONVNOP op
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// and typechecks the result with ctxExpr.
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func ConvNop(n ir.Node, t *types.Type) ir.Node {
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if types.Identical(n.Type(), t) {
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if types.IdenticalStrict(n.Type(), t) {
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return n
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}
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n = ir.NewConvExpr(base.Pos, ir.OCONVNOP, nil, n)
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22
test/typeparam/issue54537.go
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22
test/typeparam/issue54537.go
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@ -0,0 +1,22 @@
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// run
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// Copyright 2022 The Go Authors. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE file.
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package main
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func main() {
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_ = F[bool]
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var x string
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_ = G(x == "foo")
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}
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func F[T ~bool](x string) {
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var _ T = x == "foo"
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}
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func G[T any](t T) *T {
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return &t
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}
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