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spec: add Appendix with detailed type unification rules

Change-Id: I0d4ccbc396c48d565c0cbe93c9558ab330a44d02
Reviewed-on: https://go-review.googlesource.com/c/go/+/513275
Auto-Submit: Robert Griesemer <gri@google.com>
Reviewed-by: Robert Griesemer <gri@google.com>
Reviewed-by: Ian Lance Taylor <iant@google.com>
TryBot-Bypass: Robert Griesemer <gri@google.com>
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Robert Griesemer 2023-07-25 17:18:20 -07:00 committed by Robert Griesemer
parent 208fc13245
commit 03bec7dc6f

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@ -1,6 +1,6 @@
<!--{
"Title": "The Go Programming Language Specification",
"Subtitle": "Version of July 25, 2023",
"Subtitle": "Version of July 31, 2023",
"Path": "/ref/spec"
}-->
@ -4620,13 +4620,13 @@ Otherwise, type inference succeeds.
<p>
Type inference solves type equations through <i>type unification</i>.
Type unification recursively compares the LHS and RHS types of an
equation, where either or both types may be or contain type parameters,
equation, where either or both types may be or contain bound type parameters,
and looks for type arguments for those type parameters such that the LHS
and RHS match (become identical or assignment-compatible, depending on
context).
To that effect, type inference maintains a map of bound type parameters
to inferred type arguments.
Initially, the type parameters are known but the map is empty.
to inferred type arguments; this map is consulted and updated during type unification.
Initially, the bound type parameters are known but the map is empty.
During type unification, if a new type argument <code>A</code> is inferred,
the respective mapping <code>P ➞ A</code> from type parameter to argument
is added to the map.
@ -4674,9 +4674,12 @@ no unification step failed, and the map is fully populated.
<p>
Unification uses a combination of <i>exact</i> and <i>loose</i>
Unification (see Appendix) depending on whether two types have
to be <a href="#Type_identity">identical</a> or simply
<a href="#Assignability">assignment-compatible</a>:
unification depending on whether two types have to be
<a href="#Type_identity">identical</a>,
<a href="#Assignability">assignment-compatible</a>, or
only structurally equal.
The respective <a href="#Type_unification_rules">type unification rules</a>
are spelled out in detail in the <a href="#Appendix">Appendix</a>.
</p>
<p>
@ -8357,3 +8360,148 @@ The following minimal alignment properties are guaranteed:
<p>
A struct or array type has size zero if it contains no fields (or elements, respectively) that have a size greater than zero. Two distinct zero-size variables may have the same address in memory.
</p>
<h2 id="Appendix">Appendix</h2>
<h3 id="Type_unification_rules">Type unification rules</h3>
<p>
The type unification rules describe if and how two types unify.
The precise details are relevant for Go implementations,
affect the specifics of error messages (such as whether
a compiler reports a type inference or other error),
and may explain why type inference fails in unusual code situations.
But by and large these rules can be ignored when writing Go code:
type inference is designed to mostly "work as expected",
and the unification rules are fine-tuned accordingly.
</p>
<p>
Type unification is controlled by a <i>matching mode</i>, which may
be <i>exact</i> or <i>loose</i>.
As unification recursively descends a composite type structure,
the matching mode used for elements of the type, the <i>element matching mode</i>,
remains the same as the matching mode except when two types are unified for
<a href="#Assignability">assignability</a> (<code><sub>A</sub></code>):
in this case, the matching mode is <i>loose</i> at the top level but
then changes to <i>exact</i> for element types, reflecting the fact
that types don't have to be identical to be assignable.
</p>
<p>
Two types that are not bound type parameters unify exactly if any of
following conditions is true:
</p>
<ul>
<li>
Both types are <a href="#Type_identity">identical</a>.
</li>
<li>
Both types have identical structure and their element types
unify exactly.
</li>
<li>
Exactly one type is an <a href="#Type_inference">unbound</a>
type parameter with a <a href="#Core_types">core type</a>,
and that core type unifies with the other type per the
unification rules for <code><sub>A</sub></code>
(loose unification at the top level and exact unification
for element types).
</li>
</ul>
<p>
If both types are bound type parameters, they unify per the given
matching modes if:
</p>
<ul>
<li>
Both type parameters are identical.
</li>
<li>
At most one of the type parameters has a known type argument.
In this case, the type parameters are <i>joined</i>:
they both stand for the same type argument.
If neither type parameter has a known type argument yet,
a future type argument inferred for one the type parameters
is simultaneously inferred for both of them.
</li>
<li>
Both type parameters have a known type argument
and the type arguments unify per the given matching modes.
</li>
</ul>
<p>
A single bound type parameter <code>P</code> and another type <code>T</code> unify
per the given matching modes if:
</p>
<ul>
<li>
<code>P</code> doesn't have a known type argument.
In this case, <code>T</code> is inferred as the type argument for <code>P</code>.
</li>
<li>
<code>P</code> does have a known type argument <code>A</code>,
<code>A</code> and <code>T</code> unify per the given matching modes,
and one of the following conditions is true:
<ul>
<li>
Both <code>A</code> and <code>T</code> are interface types:
In this case, if both <code>A</code> and <code>T</code> are
also <a href="#Type_definitions">defined</a> types,
they must be <a href="#Type_identity">identical</a>.
Otherwise, if neither of them is a defined type, they must
have the same number of methods
(unification of <code>A</code> and <code>T</code> already
established that the methods match).
</li>
<li>
Neither <code>A</code> nor <code>T</code> are interface types:
In this case, if <code>T</code> is a defined type, <code>T</code>
replaces <code>A</code> as the inferred type argument for <code>P</code>.
</li>
<li>
In all other cases unification of <code>P</code> and <code>T</code> fails.
</li>
</ul>
</li>
</ul>
<p>
Finally, two types that are not bound type parameters unify loosely
(and per the element matching mode) if:
</p>
<ul>
<li>
Both types unify exactly.
</li>
<li>
One type is a <a href="#Type_definitions">defined type</a>,
the other type is a type literal, but not an interface,
and their underlying types unify per the element matching mode.
</li>
<li>
Both types are interfaces (but not type parameters) with
identical <a href="#Interface_types">type terms</a>,
both or neither embed the predeclared type
<a href="#Predeclared_identifiers">comparable</a>,
corresponding method types unify per the element matching mode,
and the method set of one of the interfaces is a subset of
the method set of the other interface.
</li>
<li>
Only one type is an interface (but not a type parameter),
corresponding methods of the two types unify per the element matching mode,
and the method set of the interface is a subset of
the method set of the other type.
</li>
<li>
Both types have the same structure and their element types
unify per the element matching mode.
</li>
</ul>