1
0
mirror of https://github.com/golang/go synced 2024-11-12 03:50:21 -07:00
go/test/fixedbugs/issue17318.go

48 lines
1.4 KiB
Go
Raw Normal View History

// errorcheck -0 -N -m -l
// Copyright 2016 The Go Authors. All rights reserved.
// Use of this source code is governed by a BSD-style
// license that can be found in the LICENSE file.
// The escape analyzer needs to run till its root set settles
// (this is not that often, it turns out).
// This test is likely to become stale because the leak depends
// on a spurious-escape bug -- return an interface as a named
// output parameter appears to cause the called closure to escape,
// where returning it as a regular type does not.
package main
import (
"fmt"
)
type closure func(i, j int) ent
type ent int
func (e ent) String() string {
return fmt.Sprintf("%d", int(e)) // ERROR "ent.String ... argument does not escape$" "int\(e\) escapes to heap$"
}
//go:noinline
func foo(ops closure, j int) (err fmt.Stringer) { // ERROR "leaking param: ops$" "leaking param: ops to result err level=0$"
enqueue := func(i int) fmt.Stringer { // ERROR "func literal escapes to heap$"
return ops(i, j) // ERROR "ops\(i, j\) escapes to heap$"
}
err = enqueue(4)
if err != nil {
return err
}
return // return result of enqueue, a fmt.Stringer
}
func main() {
// 3 identical functions, to get different escape behavior.
f := func(i, j int) ent { // ERROR "func literal escapes to heap$"
return ent(i + j)
}
i := foo(f, 3).(ent)
fmt.Printf("foo(f,3)=%d\n", int(i)) // ERROR "int\(i\) escapes to heap$" "main ... argument does not escape$"
}